在非聚合查询中时的聚合情况 [英] Aggregate case when inside non aggregate query

问题描述

我有一个非常庞大的查询，其最简单的形式如下:

I have a pretty massive query that in its simplest form looks like this:

select r.rep_id, u.user_id, u.signup_date, pi.application_date, pi.management_date, aum
from table1 r
left join table2 u on r.user_id=u.user_id
left join table3 pi on u.user_id=pi.user_id

我需要再添加一个条件，以使我获得每个代表的应用程序日期不为空的用户数(例如:rep 1具有3个用户的应用程序日期已填满)，并将其分配给类别(由于3个用户，rep是一个某些状态类别).看起来像这样:

I need to add one more condition that gives me count of users with non null application date per rep (like: rep 1 has 3 users with filled application dates), and assign it into categories (since 3 users, rep is a certain status category). This looks something like this:

case when sum(case when application_date is not null then 1 else 0 end) >=10 then 'status1'
   when sum(case when application_date is not null then 1 else 0 end) >=5 then 'status2'
   when sum(case when application_date is not null then 1 else 0 end) >=1  then 'status3'
   else 'no_status' end as category

但是，如果我只是将其添加到select语句中，则所有代表都将变为status1，因为sum()是在所有使用申请日期的顾问程序上完成的:

However, if I was to simply add it to the select statement, all reps will becomes of status1 because the sum() is done over all advisors with application dates filled:

select r.rep_id, u.user_id, u.signup_date, pi.application_date, pi.management_date, aum,
(
 select case when sum(case when application_date is not null then 1 else 0 end) >=10 then 'status1'
   when sum(case when application_date is not null then 1 else 0 end) >=5 then 'status2'
   when sum(case when application_date is not null then 1 else 0 end) >=1  then 'status3'
   else 'no_status' end as category
from table3
) as category
from table1 r
left join table2 u on r.user_id=u.user_id
left join table3 pi on u.user_id=pi.user_id

您能协助我在查询中添加更多内容吗?非常感激！

Can you assist with having the addition to my query to be across reps and not overall? Much appreciated!

推荐答案

根据您的描述，我认为您需要一个窗口函数:

Based on your description, I think you need a window function:

select r.rep_id, u.user_id, u.signup_date, pi.application_date, pi.management_date, aum,
       count(pi.application_date) over (partition by r.rep_id) as newcol
from table1 r left join
     table2 u
     on r.user_id = u.user_id left join
     table3 pi
     on u.user_id = pi.user_id;

如果您愿意，可以在case中使用count()来获取范围.

You can use the count() in a case to get ranges, if that is what you prefer.

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