AWS CLI S3存储桶删除具有日期条件的对象 [英] aws cli s3 bucket remove object with date condition

问题描述

我如何递归删除aws cli s3存储桶中具有日期条件的对象

how do i remove aws cli s3 bucket remove object with date condition recursively

我正在使用此命令进行列表

i am using this command for listing

aws s3 ls --recursive s3://uat-files-transfer-storage/ | awk '$1 < "2018-02-01 11:13:29" {print $0}' | sort -n

它运行得很好，但是当我将此命令与rm一起使用时，它会删除所有文件

its run perfectly but when i use this command with rm its delete all files

aws s3 rm --recursive s3://uat-files-transfer-storage/ | awk '$1 < "2018-02-01 11:13:29" {print $0}' | sort -n

任何解决方案

推荐答案

您处在正确的轨道上.要了解发生了什么，让我们逐步查看您的命令正在做什么.

You're on the right track. To understand what's going on, let's look at what your commands are doing step by step.

aws s3 ls --recursive s3://uat-files-transfer-storage/ | awk '$1 < "2018-02-01 11:13:29" {print $0}' | sort -n

此命令以递归方式列出存储桶中的所有文件，检查输出是否符合特定条件，然后对结果输出行进行排序.

This command lists all files in the bucket recursively, checks the output for a specific condition, and then sorts the resultant output lines.

aws s3 rm --recursive s3://uat-files-transfer-storage/ | awk '$1 < "2018-02-01 11:13:29" {print $0}' | sort -n

此命令以递归方式删除存储桶中的所有文件，检查特定条件下的输出，然后对结果输出行进行排序.因此，第二个命令将首先删除您的所有文件！

This command deletes all the files in your bucket recursively, checks the output for a specific condition, and then sorts the resultant output lines. So the second command deletes all your files first!

您要做的是列出存储桶中的所有文件，检查它们是否符合特定条件，然后然后将其删除.这应该起作用:

What you want to do is list all the files in your bucket, check that they meet a certain criteria, and then delete them. This should work:

aws s3 ls --recursive s3://uat-files-transfer-storage/ | awk '$1 < "2018-02-01 11:13:29" {print $4}' | xargs -n1 -t -I 'KEY' aws s3 rm s3://uat-files-transfer-storage/'KEY'

请小心！这不会在删除之前提示您，这是一种错误地清理整个存储桶的简便方法.

BE CAREFUL! This won't prompt you before deleting, and it's an easy way to clean out your whole bucket by mistake.

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