查询字符串参数的值不能包含'='分隔符 [英] the value of a query string parameter may not contain a '=' delimiter
问题描述
现在我简化问题.
我尝试直接复制并粘贴查询以使用％3D而不是'='对其进行确认
I try to directly copy and paste the query to confrim it use %3D instead of '='
var xhrSNS = Ti.Network.createHTTPClient({
onload :function(e) {
Ti.API.info("test Post query:" + JSON.stringify(e));
Ti.API.info(this.responseText);
},
onerror : function(e){
Ti.API.debug("test Create PlatForm Endpoint registerPush error:" + e.error);
Ti.API.info(this.responseText);
}
});
getUrl = "http://sns.ap-northeast-1.amazonaws.com?AWSAccessKeyId=AAAAAAAAAAAAAAA&Action=CreatePlatformEndpoint&PlatformApplicationArn=arn%3Aaws%3Asns%3Aap-northeast-1%3A776188326341%3Aapp%2FGCM%2Fmyapp&SignatureMethod=HmacSHA256&SignatureVersion=2&Timestamp=2016-04-03T15%3A05%3A51.465Z&Token=APA91bEiaB-902cRmwwgCwoqi2jRIJzzTIZNB7XduELuBKit_WF29tN5twrVW5t1BHpj07ARgwjzoc-I5xVur5K6I6ZQcnoErguUyi-VBHvuI5eY9HS4jq1J6KbIC05Etoe8indjpY9X&Version=2010-03-31&Signature=DzxQpP%2BcALS91C53eia6ZkBhxg3lQ32ctqiEmqKwwLA%3D";
xhrSNS.open('GET',getUrl);
xhrSNS.send();
请参阅getUrl的最后一个字母，它一定使用'％3D'.
Please see the last letter of getUrl, it surely use '%3D'.
但是收益是一样的.
有人抱怨句子中包含'='分隔符.
It makes a complaint that sentence include '=' delimiter.
[DEBUG] test Create PlatForm Endpoint registerPush error:400 : Bad Request
[INFO] <ErrorResponse xmlns="http://webservices.amazon.com/AWSFault/2005-15-09">
[INFO] <Error>
[INFO] <Type>Sender</Type>
[INFO] <Code>MalformedQueryString</Code>
[INFO] <Message>AWSAccessKeyId=AAAAAAAAAAAAAAA&Action=CreatePlatformEndpoint&PlatformApplicationArn=arn%3Aaws%3Asns%3Aap-northeast-1%3A776188326341%3Aapp%2FGCM%2Fmyapp&SignatureMethod=HmacSHA256&SignatureVersion=2&Timestamp=2016-04-03T15%3A05%3A51.465Z&Token=APA91bEiaB-902cRmwwgCwoqi2jRIJzzTIZNB7XduELuBKit_WF29tN5twrVW5t1BHpj07ARgwjzoc-I5xVur5K6I6ZQcnoErguUyi-VBHvuI5eY9HS4jq1J6KbIC05Etoe8indjpY9X&Version=2010-03-31&Signature=DzxQpP%2BcALS91C53eia6ZkBhxg3lQ32ctqiEmqKwwLA= is not valid; the value of a query string parameter may not contain a '=' delimiter</Message>
-----------------------------添加到此处--------------- -
-----------------------------adding until here-----------------
我正在使用Amazon SNS API
I am using Amazon SNS API
我这样创建了url，使其在浏览器中也能很好地工作.
I made url like this it works well on browser.
http://sns.ap-northeast-1.amazonaws.com?AWSAccessKeyId=AAAAAAAAAAAAA&Action=CreatePlatformEndpoint&PlatformApplicationArn=arn%3Aaws%3Asns%3Aap-northeast-1%3A776188326341%3Aapp%2FGCM%2Fmyapp&SignatureMethod=HmacSHA256&SignatureVersion=2&Timestamp=2016-04-01T21%3A06%3A29.861Z&Token=APA91bEiaB-902cRmwwgCwoqi2jRIJzzTIZNB7XduELuBKit_WF29tN5twrVW5t1BHpj07ARgwjzoc-I5xVur5K6I6ZQcnoErguUyi-VBHvuI5eY9HS4jq1J6KbIC05Etoe8indjpY9X&Version=2010-03-31&Signature=Dt9tXa0Rjl%2Ff6YxZ4JaPfsm%2BT%2BMX03gS712nIKKekAI%3D
但是，如果我尝试从Android进行尝试.
However if I try from Android.
这将返回400个错误的请求.
This returns 400 bad request.
<ErrorResponse xmlns="http://webservices.amazon.com/AWSFault/2005-15-09">
<Error>
<Type>Sender</Type>
<Code>MalformedQueryString</Code>
<Message>AWSAccessKeyId=AAAAAAAAAAAAA&Action=CreatePlatformEndpoint&PlatformApplicationArn=arn%3Aaws%3Asns%3Aap-northeast-1%3A776188326341%3Aapp%2FGCM%2Fmyapp&SignatureMethod=HmacSHA256&SignatureVersion=2&Timestamp=2016-04-01T21%3A06%3A29.861Z&Token=APA91bEiaB-902cRmwwgCwoqi2jRIJzzTIZNB7XduELuBKit_WF29tN5twrVW5t1BHpj07ARgwjzoc-I5xVur5K6I6ZQcnoErguUyi-VBHvuI5eY9HS4jq1J6KbIC05Etoe8indjpY9X&Version=2010-03-31&Signature=Dt9tXa0Rjl%2Ff6YxZ4JaPfsm%2BT%2BMX03gS712nIWUekAI=
is not valid; the value of a query string parameter may not contain a '=' delimiter</Message>
</Error>
<RequestId>5b40d988-af34-577a-8839-96f04a217dec</RequestId>
</ErrorResponse>
我认为
查询字符串参数的值不能包含'='分隔符
the value of a query string parameter may not contain a '=' delimiter
是造成问题的原因，但我不知道如何解决.
is the cause of problem though, I cant figure out how to fix it.
相同的代码可在iPhone上使用.
The same code works on iPhone.
仅在android上不起作用.
it doesn't work only from android.
我通过此函数制作了URL字符串
I made URL strings from this function
var array = {
PlatformApplicationArn : Ti.App.global.androidArn
};
awsObj = getSignature("CreatePlatformEndpoint",date,awsUrl,event.registrationId,array);
var getUrl = "http://" + awsUrl + '?' + awsObj.str_para + "&Signature=" + awsObj.encodedString;
Ti.API.info('GETurl :' + getUrl);
xhrSNS.open('GET',getUrl);
function getSignature(action,date,awsUrl,token,array){
Ti.include('/jssha/jssha256.js');
var base = {
Action:action,
AWSAccessKeyId : Ti.App.global.awsAccessKey,
SignatureMethod : "HmacSHA256",
SignatureVersion :2,
Token: token,
Timestamp : date,
Version : "2010-03-31",
};
para = arrayMerge(array,base);
var para_array = [];
for(var pname in para){
para_array.push(pname + "=" + encodeURIComponent(para[pname]));
}
para_array.sort();
var str_para = para_array.join('&');
var str_signature = "GET" + "\n" + awsUrl + "\n" + "/" + "\n" + str_para;
console.log("str_signature:" + str_signature);
HMAC_SHA256_init(Ti.App.global.awsSecretKey);
HMAC_SHA256_write(str_signature);
var array_hash = HMAC_SHA256_finalize();
var str_hash = "";
for (var i = 0; i < array_hash.length; i++) {
str_hash += String.fromCharCode(array_hash[i]);
}
var awsObj = new Object();
awsObj.encodedString = encodeURIComponent(base64encode(str_hash));
Ti.API.info("awsObj.encodedString:" + awsObj.encodedString); // I have confirmed encodedString is correct here.
awsObj.str_para = str_para;
return awsObj;
}
推荐答案
浏览器中的网址:Signature = Dt9tXa0Rjl％2Ff6YxZ4JaPfsm％2BT％2BMX03gS712nIKKekAI％3D
URL in browser: Signature=Dt9tXa0Rjl%2Ff6YxZ4JaPfsm%2BT%2BMX03gS712nIKKekAI%3D
Android中的URL:签名= Dt9tXa0Rjl％2Ff6YxZ4JaPfsm％2BT％2BMX03gS712nIWUekAI =
URL in Android: Signature=Dt9tXa0Rjl%2Ff6YxZ4JaPfsm%2BT%2BMX03gS712nIWUekAI=
这篇关于查询字符串参数的值不能包含'='分隔符的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
