Android Persistence room:“无法弄清楚如何从游标读取此字段" [英] Android Persistence room: "Cannot figure out how to read this field from a cursor"
问题描述
我正在尝试使用新的Android Persistence Room Library在两个数据库表之间创建关系.我查看了文档,并尝试实现在 https:中找到的示例://developer.android.com/reference/android/arch/persistence/room/Relation.html :
I'm trying to create a relation between two database tables using the new Android Persistence Room Library. I looked at the documentation and tried to implement the example found at https://developer.android.com/reference/android/arch/persistence/room/Relation.html:
@Entity
public class User {
@PrimaryKey
int id;
}
@Entity
public class Pet {
@PrimaryKey
int id;
int userId;
String name;
}
@Dao
public interface UserDao {
@Query("SELECT * from User")
public List<User> loadUser();
}
@Dao
public interface PetDao {
@Query("SELECT * from Pet")
public List<Pet> loadUserAndPets();
}
public class UserAllPets {
@Embedded
public User user;
@Relation(parentColumn = "user.id", entityColumn = "userId", entity = Pet.class)
public List pets;
}
@Dao
public interface UserPetDao {
@Query("SELECT * from User")
public List<UserAllPets> loadUserAndPets();
}
我收到以下错误
...error: Cannot figure out how to read this field from a cursor.
关于:
private java.util.List<?> pets;
我想指出的是,我在他们的文档中发现了一些令人困惑的地方.例如,缺少@PrimaryKey
以及User
类缺少@Entity
批注的事实,尽管它应该是一个实体(如我所见,它很受欢迎).有人遇到过同样的问题吗?提前谢谢
I would like to point out that I found some things in their docs really confusing. For example the lack of @PrimaryKey
and also the fact that the User
class is missing the @Entity
annotation, although it's supposed to be an entity (as fas as I see it). Did anybody run into the same problem? Thanks a lot in advance
推荐答案
Document is really confusing. Try with just below classes:
1)用户实体:
@Entity
public class User {
@PrimaryKey
public int id; // User id
}
2)宠物实体:
@Entity
public class Pet {
@PrimaryKey
public int id; // Pet id
public int userId; // User id
public String name;
}
3)UserWithPets POJO:
// Note: No annotation required at this class definition.
public class UserWithPets {
@Embedded
public User user;
@Relation(parentColumn = "id", entityColumn = "userId", entity = Pet.class)
public List<Pet> pets; // or use simply 'List pets;'
/* Alternatively you can use projection to fetch a specific column (i.e. only name of the pets) from related Pet table. You can uncomment and try below;
@Relation(parentColumn = "id", entityColumn = "userId", entity = Pet.class, projection = "name")
public List<String> pets;
*/
}
-
parentColumn
引用嵌入式User
表的id
列 -
entityColumn
引用Pet
表的userId
(User
-Pet
关系)列, -
entity
引用与User
表有关系的表(Pet
). parentColumn
refers to EmbeddedUser
table'sid
column,entityColumn
refers toPet
table'suserId
(User
-Pet
relation) column,entity
refers to table(Pet
) which has relation withUser
table.
4)UserDao Dao:
@Dao
public interface UserDao {
@Query("SELECT * FROM User")
public List<UserWithPets> loadUsersWithPets();
}
现在尝试loadUsersWithPets()
,它将返回用户及其宠物列表.
Now try loadUsersWithPets()
, which returns the users with their list of pets.
编辑:请参阅我的其他答案.
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