Android Espresso将具有不同色调的BitmapDrawables匹配 [英] Android Espresso match BitmapDrawables with different tint

问题描述

有什么方法可以比较由BitmapDrawable包裹的两个Bitmaps.

Is there some way to compare two Bitmaps which are wrapped by the BitmapDrawable.

如果大小不匹配，则比较应该不会失败，但是应该匹配像素和Bitmap

The comparison should not fail if the sizes doesn't match, but it should match pixels and the color of the Bitmap

我不确定Android的本机部分如何绘制Bitmap，因为因为sameAs即使色泽颜色不同也返回true.

I am not sure how the native part of Android draws the Bitmap, because sameAs returns true even though the tint color is different.

如果大小不同，我可以彼此创建缩放的Bitmap并将其与之比较.

If the size is different, I can create scaled Bitmap from the other and the compare these to.

在我的源代码中，我将DrawableCompat.setTint与ImageViews Drawable一起使用，并且在测试代码中，我从资源中加载了Drawable并对其进行了相同的着色.

In my source code I use DrawableCompat.setTint with the ImageViews Drawable and in the test code I load Drawable from resources and tint it same way.

有什么想法吗?我想进行一次测试，以根据是否按下ImageView来验证ImageView的来源Drawable和颜色.

Any ideas? I would like to have test which validates the source Drawable of ImageView and the color as well based on if it's pressed or not.

注意1:我的可绘制对象为白色，并且使用色调设置颜色. Bitmaps的循环像素不起作用，因为此时像素为白色，最有可能是Android本机面在绘制时使用淡色.

NOTE 1: My drawables are white, and I use tint to set color. Looping pixels for Bitmapsdoesn't work because they are white at that point, most likely Android native side uses tint color when drawing.

注意2:使用compile 'com.android.support:palette-v7:21.0.0'和Palette.from(bitmap).generate();都没有帮助，因为返回的调色板具有0个色板，因此无法在此获取任何颜色信息.

NOTE 2: Using compile 'com.android.support:palette-v7:21.0.0' and Palette.from(bitmap).generate(); doesn't help either because the returned palette has 0 swatches so can't get any color information there.

这是我当前的匹配者:

public static Matcher<View> withDrawable(final Drawable d) {
    return new BoundedMatcher<View, ImageView>(ImageView.class) {

        @Override
        public boolean matchesSafely(ImageView iv) {
            if (d == null) {
                return iv.getDrawable() == null;
            } else if (iv.getDrawable() == null) {
                return false;
            }

            if (d instanceof BitmapDrawable && iv.getDrawable() instanceof BitmapDrawable) {
                BitmapDrawable d1 = (BitmapDrawable) d;
                BitmapDrawable d2 = (BitmapDrawable) iv.getDrawable();

                Bitmap b1 = d1.getBitmap();
                Bitmap b2 = d2.getBitmap();

                return b1.sameAs(b2);
            }

            return iv.getDrawable().getConstantState().equals(d.getConstantState());
        }

        @Override
        public void describeTo(Description description) {
            description.appendText("with drawable: ");
        }
    };
}

谢谢.

推荐答案

我遇到了相反的问题:当可绘制对象的大小和/或色调可以更改时，匹配它.

I've had the opposite issue: matching a drawable when it's size and/or tint can change.

当我将drawable转换为位图时，我使用它的默认大小并应用黑色:

When I convert drawable to bitmap, I use it's default size and apply a black tint:

private fun getBitmapFromDrawable(drawable: Drawable): Bitmap {
    val bitmap: Bitmap = Bitmap.createBitmap(
        drawable.intrinsicWidth,
        drawable.intrinsicHeight,
        Bitmap.Config.ARGB_8888
    )

    val canvas = Canvas(bitmap)
    drawable.apply {
        setBounds(0, 0, canvas.width, canvas.height)
        setTint(Color.BLACK)
        draw(canvas)
    }

    return bitmap
}

用法:

val bitmap = getBitmapFromDrawable(currentDrawable)
val otherBitmap = getBitmapFromDrawable(otherDrawable)

return bitmap.sameAs(otherBitmap)

您可以使用新参数来匹配可绘制颜色...

You could use a new parameter for matching the drawable color...

private fun getBitmapFromDrawable(drawable: Drawable, color:Int): Bitmap {
    val bitmap: Bitmap = Bitmap.createBitmap(
        drawable.intrinsicWidth,
        drawable.intrinsicHeight,
        Bitmap.Config.ARGB_8888
    )

    val canvas = Canvas(bitmap)
    drawable.apply {
        setBounds(0, 0, canvas.width, canvas.height)
        setTint(color)
        draw(canvas)
    }

    return bitmap
}

用法:

val bitmap = getBitmapFromDrawable(currentDrawable, color)
val otherBitmap = getBitmapFromDrawable(otherDrawable, color)

return bitmap.sameAs(otherBitmap)

这篇关于Android Espresso将具有不同色调的BitmapDrawables匹配的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！