多个edittext仅具有一个textwatcher在android中进行计算 [英] multiple edittext with only one textwatchers for calculation in android

问题描述

我将从第一个EditText中获取一个值，并从第二个EditText中获取另一个值，两个值都将被计算并在第三个EditText中显示结果，而第三个EditText在android中仅使用一个TextWatcher. 请帮我谢谢你.

I will get a value from first EditText and one more value from second EditText both values are calculated and show the result in third EditText which is using only one TextWatcher in android. Please help me thank you.

public class TextWatcher_Activity extends Activity {
    private EditText passwordEditText, passwordEditText1, passwordEditText2;
    private TextView textView;
    private View view;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_textwatcher);

        /* Initializing views */
        passwordEditText = (EditText) findViewById(R.id.password);
        textView = (TextView) findViewById(R.id.passwordHint);
        textView.setVisibility(View.GONE);

        passwordEditText1 = (EditText) findViewById(R.id.password1);
        passwordEditText2 = (EditText) findViewById(R.id.password2);

 passwordEditText.addTextChangedListener(passwordWatcher);
        passwordEditText1.addTextChangedListener(passwordWatcher);
        passwordEditText2.addTextChangedListener(passwordWatcher);  
}
     private final TextWatcher passwordWatcher = new TextWatcher() {
            public void beforeTextChanged(CharSequence s, int start, int count, int after) {

            }

            public void onTextChanged(CharSequence s, int start, int before, int count) {
                textView.setVisibility(View.VISIBLE);
            }

            public void afterTextChanged(Editable s) {


               *//* if (s.hashCode() == passwordEditText.getText().hashCode()) {
                    //Do else something with input.
                } else if (s.hashCode() == passwordEditText1.getText().hashCode()) {
                    //Do something else useful with input.
                }*//*

                switch (view.getId()) {
                    case R.id.password:
                        //doStuff(1);
                        if (s.length() == 0) {
                            textView.setVisibility(View.GONE);
                        } else {
                            textView.setText("You have entered : " + passwordEditText.getText());
                        }
                        break;
                    case R.id.password1:
                        //doStuff(2);
                        if (s.length() == 0) {
                            textView.setVisibility(View.GONE);
                        } else {
                            textView.setText("You have entered : " + passwordEditText1.getText());
                        }
                        break;
                    case R.id.password2:
                        if (s.length() == 0) {
                            textView.setVisibility(View.GONE);
                        } else {
                            textView.setText("You have entered : " + passwordEditText2.getText());
                        }
                        break;
                }
            }
        };

推荐答案

您可以使用此方法并根据您的代码进行调整

You can use this method and ajust to your code

private void calculate(EditText editText1, EditText editText2, final EditText editText3) {
        final int[] value1 = {0};
        final int[] value2 = {0};
        final int[] total = {0};
        editText1.addTextChangedListener(new TextWatcher() {
            @Override
            public void beforeTextChanged(CharSequence s, int start, int count, int after) {}

            @Override
            public void onTextChanged(CharSequence s, int start, int before, int count) {
                value1[0] = Integer.parseInt(s.toString());
                total[0] = value1[0] + value2[0];
                editText3.setText(total[0]);
            }

            @Override
            public void afterTextChanged(Editable s) {}
        });
        editText2.addTextChangedListener(new TextWatcher() {
            @Override
            public void beforeTextChanged(CharSequence s, int start, int count, int after) {}

            @Override
            public void onTextChanged(CharSequence s, int start, int before, int count) {
                value2[0] = Integer.parseInt(s.toString());
                total[0] = value1[0] + value2[0];
                editText3.setText(total[0]);
            }

            @Override
            public void afterTextChanged(Editable s) {}
        });
    }

editText3总共具有editText1 + editText2

editText3 has total of editText1 + editText2

这篇关于多个edittext仅具有一个textwatcher在android中进行计算的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！