从片段中删除片段 [英] Removing a Fragment from a Fragment

问题描述

我有一个Activity创建了Fragment，然后此Fragment创建了另一个Fragment:

I have an Activity that creates a Fragment and then this Fragment creates another Fragment:

活动-> Fragment1-> Fragment2

我现在在Fragment2中，我想通过单击按钮返回到Fragment1.

I am now in Fragment2 and I'd like to go back to Fragment1 by clicking on a button.

在我的button的OnClickListener中，我有:

getActivity().getSupportFragmentManager().beginTransaction().remove(fragment2.this).commit();

这使我进入Activity.实际上有一种方法可以删除Fragment2并转到Fragment1吗?

This brings me to the Activity. Is there actually a way to just remove Fragment2 and go to Fragment1?

在此先感谢您的宝贵时间，我在网上找不到任何合适的信息！

Thank you in advance for your time, I could not find any suitable info online!

推荐答案

@AhmedAbidi对您的问题有很好的了解，是的，正确实施popBackStack可能会解决您的问题.但是无论如何，我想提出一种不同的方法来处理这种情况.

@AhmedAbidi has a nice insight to your problem and yes, implementing popBackStack properly may solve your problem. But anyway, I would like to suggest a different approach to handle this type of situations.

在Activity中编写两个公共函数，以在片段之间进行切换.

Write two public functions in your Activity to switch between your fragments.

public void switchToFragment1() {
    getSupportFragmentManager().beginTransaction()
        .replace(R.id.fragment_container, new Fragment1()).commit();
}

public void switchToFragment2() {
    getSupportFragmentManager().beginTransaction()
        .replace(R.id.fragment_container, new Fragment2()).commit();
}

现在从按钮中单击Fragment1，您可以通过

Now from the button click in your Fragment1 you might launch the Fragment2 via,

((YourActivity) getActivity()).switchToFragment2();

与切换到Fragment1

((YourActivity) getActivity()).switchToFragment1();

这篇关于从片段中删除片段的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！