启动服务会引发IllegalAccessException [英] Starting a Service throws an IllegalAccessException
问题描述
我有一个Service
,它可以接收音频文件并用MediaPlayer
播放.这就是我叫我的Service
:
I have a Service
which takes in an audio file and plays it with MediaPlayer
. This is how I call my Service
:
private void playAudio(String url) throws Exception {
Intent music = new Intent(this,MusicService.class);
music.putExtra("paths", path);
startService(music);
}
这是我的Service
课:
class MusicService extends Service implements OnCompletionListener {
MediaPlayer mediaPlayer;
String musicFile;
@Override
public void onCreate() {
mediaPlayer = new MediaPlayer();
mediaPlayer.setOnCompletionListener(this);
Toast.makeText(getApplicationContext(), "hello", Toast.LENGTH_LONG).show();
}
@Override
public int onStartCommand(Intent intent, int flags, int startId) {
Bundle e = intent.getExtras();
musicFile= e.getString("paths");
try {
mediaPlayer.prepare();
mediaPlayer.setDataSource(musicFile);
} catch (IllegalArgumentException i) {
// TODO Auto-generated catch block
i.printStackTrace();
} catch (IllegalStateException i) {
// TODO Auto-generated catch block
i.printStackTrace();
} catch (IOException i) {
// TODO Auto-generated catch block
i.printStackTrace();
}
if (!mediaPlayer.isPlaying()) {
mediaPlayer.start();
}
return START_STICKY;
}
@Override
public void onCompletion(MediaPlayer mp) {
// TODO Auto-generated method stub
}
@Override
public IBinder onBind(Intent arg0) {
// TODO Auto-generated method stub
return null;
}
}
Service
永远不会执行,Toast
永远不会显示,并且MediaPlayer
不会播放.
The Service
is never getting executed, the Toast
is never shown, and the MediaPlayer
does not play.
我在清单中这样声明它:
I declare my it in my manifest like this:
<service android:name=".MusicService" android:enabled="true"></service>
我收到一个强制关闭错误,并且在我的日志中出现了这个IllegalAccessException
:
I get a force close error, and this IllegalAccessException
in my logs:
java.lang.RuntimeException: Unable to instantiate service unjustentertainment.com.MusicService:
java.lang.IllegalAccessException: access to class not allowed
推荐答案
您得到的异常是因为系统由于无法访问而无法初始化您的服务(调用其构造函数).
The exception you get is because the system could not init your service (call its constructor) because its not accessible.
此处:
...确保班级是 宣布公开...
...Make sure the class is declared public...
您发布的课程不是公开的,因此将其公开.
The class you posted is not public, so make it public.
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