错误的x和y坐标Android [英] Getting wrong x and y coordinates Android
本文介绍了错误的x和y坐标Android的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
protected void setQuickActionListener(View button) {
float density = mActivity.getResources().getDisplayMetrics().density;
WindowManager.LayoutParams wmlp = mActivity.getWindow().getAttributes();
button.getLocationInWindow(location);
Toast.makeText(mActivity, " l1 " + location[0] + " l2 " + location[1],Toast.LENGTH_LONG).show();
wmlp.gravity = Gravity.TOP | Gravity.LEFT;
wmlp.x = location[0]+ (int) (((button.getWidth() / 2) + button.getHeight() / 4) / density);
wmlp.y = location[1] + (int) ((button.getHeight() - 60) / density);
mQuickAction.show(button, (int) wmlp.x, (int) wmlp.y);
}
在这里，我用于获取ImageButton单击侦听器的x y值的方法以显示快速的动作视图，而这是用于动作视图的show方法的代码.
here the method i am using to get x y values for an ImageButton click listener to show quick action views and this the code for show method for action views.
public void show(View anchor, int xPos, int yPos) {
preShow();
mDidAction = false;
int[] location = new int[2];
anchor.getLocationOnScreen(location);
Rect anchorRect = new Rect(location[0], location[1], location[0] + anchor.getWidth(), location[1]
+ anchor.getHeight());
mRootView.setLayoutParams(new LayoutParams(LayoutParams.WRAP_CONTENT, LayoutParams.WRAP_CONTENT));
mRootView.measure(LayoutParams.WRAP_CONTENT, LayoutParams.WRAP_CONTENT);
int rootHeight = mRootView.getMeasuredHeight();
int rootWidth = mRootView.getMeasuredWidth();
if (rootWidth == 0) {
rootWidth = mRootView.getMeasuredWidth();
}
int screenWidth = mWindowManager.getDefaultDisplay().getWidth();
int screenHeight = mWindowManager.getDefaultDisplay().getHeight();
arrowPos = anchorRect.centerX()-xPos;
int dytop = anchorRect.top;
int dybottom = screenHeight/4;
boolean onTop = (dytop > dybottom) ? true : false;
LinearLayout.LayoutParams rlpms;
// xPos > (screenWidth - 100
int dyleft = xPos;
int dyright = screenWidth - screenWidth/10;
boolean onRight = (dyleft > dyright) ? true : false;
if (onRight) {
if(onTop){
yPos = anchorRect.top - rootHeight/3;
im1 =(ImageView) mRootView.findViewById(R.id.arrow_down);
rlpms=new LinearLayout.LayoutParams(RelativeLayout.LayoutParams.WRAP_CONTENT,LinearLayout.LayoutParams.WRAP_CONTENT);
android.widget.LinearLayout.LayoutParams lp = (android.widget.LinearLayout.LayoutParams) im1.getLayoutParams();
lp.setMargins(0,rootHeight/3,0 ,0);
im1.setLayoutParams(lp);
Log.d("ddsaf", ""+onTop);
}
else
{
im1 =(ImageView) mRootView.findViewById(R.id.arrow_down);
rlpms=new LinearLayout.LayoutParams(LinearLayout.LayoutParams.WRAP_CONTENT,LinearLayout.LayoutParams.WRAP_CONTENT);
android.widget.LinearLayout.LayoutParams lp = (android.widget.LinearLayout.LayoutParams) im1.getLayoutParams();
lp.setMargins(0,5,0 ,0);
im1.setLayoutParams(lp);
//Log.d("ddsaf", ""+onTop);
}
xPos = anchorRect.left - rootWidth;
} else {
if(onTop){
yPos = anchorRect.top - rootHeight/3;
im1 =(ImageView) mRootView.findViewById(R.id.arrow_up);
rlpms=new LinearLayout.LayoutParams(LinearLayout.LayoutParams.WRAP_CONTENT,LinearLayout.LayoutParams.WRAP_CONTENT);
android.widget.LinearLayout.LayoutParams lp = (android.widget.LinearLayout.LayoutParams) im1.getLayoutParams();
lp.setMargins(0,rootHeight/3,0 ,0);
im1.setLayoutParams(lp);
//Log.d("ddsaf", "top "+onTop);
}
else
{
im1 =(ImageView) mRootView.findViewById(R.id.arrow_up);
rlpms=new LinearLayout.LayoutParams(LinearLayout.LayoutParams.WRAP_CONTENT,LinearLayout.LayoutParams.WRAP_CONTENT);
android.widget.LinearLayout.LayoutParams lp = (android.widget.LinearLayout.LayoutParams) im1.getLayoutParams();
lp.setMargins(0,5,0 ,0);
im1.setLayoutParams(lp);
//Log.d("ddsaf", ""+onTop);
}
xPos = xPos+rootWidth/4;
}
Log.d("ddsaf", ""+anchorRect.left);
showArrow(((onRight) ? R.id.arrow_down : R.id.arrow_up), arrowPos);
setAnimationStyle(screenWidth, anchorRect.centerX(), onRight);
mWindow.showAtLocation(anchor, Gravity.NO_GRAVITY, xPos, yPos);}
问题是我在错误的位置上获得了快速的操作视图，即在infalted布局中一次出现在0,0时，为什么在下面发生这种情况的任何想法都是使用 *
problem is i am getting quick action views at wrong postions ie at 0,0 once in while on infalted layout any idea why this happens below is where it has been infalted to with *
<LinearLayout
android:id="@+id/lyt_xx"
android:layout_width="0dp"
android:layout_height="match_parent"
android:layout_weight="60"
android:orientation="horizontal"
android:padding="@dimen/padding_small" >
<ImageView
android:id="@+id/img_separator"
android:layout_width="30dp"
android:layout_height="fill_parent"
android:layout_marginLeft="@dimen/padding_small"
android:layout_marginRight="@dimen/padding_small"
android:background="#333333" />
<LinearLayout
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:orientation="horizontal" >
***<com.apps.horizontalgrid.TwoWayGridView
xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:app="http://schemas.android.com/apk/res-auto"
android:id="@+id/xx_gridview"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:background="@color/background"
android:padding="@dimen/padding_small"
app:cacheColorHint="#00000000"
app:gravity="fill"
app:horizontalSpacing="@dimen/padding_small"
app:numColumns="auto_fit"
app:numRows="2"
app:rowHeight="260dp"
app:scrollDirectionLandscape="horizontal"
app:scrollDirectionPortrait="horizontal"
app:verticalSpacing="@dimen/padding_small" >
</com.apps.horizontalgrid.TwoWayGridView>***
</LinearLayout>
<!-- -->
</LinearLayout>
<!-- -->
推荐答案
每个View对象/子类都可以访问执行此操作的方法.
Each View object/subclass has access to methods which do exactly this.
View.getTop(); // Top position of this view relative to its parent.
View.getLeft(); // Left position of this view relative to its parent.
View.getRight(); // Right position of this view relative to its parent.
View.getBottom(); // Bottom position of this view relative to its parent.
在调用任何这些方法之前，必须确保已显示View，否则您将获得0或最糟糕的是NPE.
You have to ensure that the View has been displayed prior to calling any of these methods, otherwise you'll get 0 or at worst an NPE.
请记住，这些返回相对于View父级的位置.如果您想要视图的实际绝对位置，则需要使用以下方法:
Bear in mind, these return positions relative to a View's parent. If you want the actual absolute position of the View, then you will need to use the method(s):
View.getLocationInWindow(); // Computes the coordinates of this view in its window.
or
View.getLocationOnScreen(); // Computes the coordinates of this view on the screen.
无需重新发明轮子.可以在这里找到更多信息: http://developer.android.com/reference/android/view/View.html
There is no need to reinvent the wheel. Further information can be found here: http://developer.android.com/reference/android/view/View.html
这篇关于错误的x和y坐标Android的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
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