如何轻松地遍历"strings.xml"中的所有字符串.资源文件? [英] How to easily iterate over all strings within the "strings.xml" resource file?

问题描述

我创建了一个使用TTS引擎向用户发送反馈的应用程序.为了提高性能，我使用了synthesizeToFile和addSpeech方法，但是要合成的文本字符串位于strings.xml文件内部，因此我必须针对由TTS引擎.

I created an application that uses the TTS engine to send feedback to the user. With the aim to improve the performance, I used the synthesizeToFile and addSpeech methods, but strings of text to be synthesized are inside the strings.xml file, so I have to invoke these methods for each string that is spoken by the TTS engine.

由于TTS引擎仅使用名称以tts_开头的字符串，是否可以轻松地遍历strings.xml文件中以tts_开头的所有字符串?

Since the TTS engine uses only strings whose name begins with tts_, is it possible to easily iterate over all strings that begin with tts_ within the strings.xml file?

推荐答案

您可以(在定义时)将所有资源名称都指定为"prefix"+(1..n).在代码中，

You can give them all (while defining) the resource name as "prefix"+(1..n). And in the code use,

int resid=<constant>;
for(i=1;resid!=0;i++){
        resid = this.getResources().getIdentifier("prefix"+i, "strings", this.getPackageName());
}

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