如何使用“房间关系"获取其他pojo的列表 [英] How to use Room Relation to get a list of another pojo
本文介绍了如何使用“房间关系"获取其他pojo的列表的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
@Entity(tableName = "subscription")
data class Subscription(
@PrimaryKey val planId: Int,
@ColumnInfo(name = "plan_name") val planName: String? = null,
@ColumnInfo(name = "plan_description") val planDescription: String? = null,
@ColumnInfo(name = "plan_reg_fee") val planRegFee: String? = null,
@ColumnInfo(name = "plan_monthly_charge") val planMonthlyCharge: String? = null
)
data class Benefit(
@ColumnInfo(name = "benefit_id") val benefitId: Int? = null,
@ColumnInfo(name = "benefit_code") val benefitCode: Int? = null,
@ColumnInfo(name = "benefit_name") val benefitName: String? = null,
@ColumnInfo(name = "benefit_status") val benefitStatus: String? = null
)
如何在订阅"中获取福利列表,即
how to get a list of Benefit inside Subscription i.e.,
val benefitList: LiveData<List<Benefit>>? = null
使用房间关系
推荐答案
您可以从 Google文档. 有一些有关房间中的关系"的示例.
You can find examples from Google Documents. There are examples about Relation in Room.
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