错误的base-64错误 [英] Bad base-64 error

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本文介绍了错误的base-64错误的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我在以下代码中收到"java.lang.IllegalArgumentException:错误的base-64":

I'm getting a "java.lang.IllegalArgumentException: bad base-64" on the following code:

byte[] msgBytes = Base64.decode(msgStr, Base64.NO_WRAP);

msgString是一个字符串,在此行之前,我检查了msgStr的值,它是"fl-ILw ==.有什么问题吗?

msgString is a String, and right before this line, I check the value of msgStr and it is "fl-ILw==". Is there anything wrong?

谢谢.

推荐答案

根据RFC 4648( http://www.rfc-editor.org/rfc/rfc4648.txt )'-'字符不是有效的Base64字符,但另一方面对于"URL和文件名安全的Base 64字母"有效

According to RFC 4648(http://www.rfc-editor.org/rfc/rfc4648.txt) '-' character is not a valid Base64 character but on the other hand is valid for "URL and Filename safe Base 64 Alphabet".

因此,您可以根据字符串的预期格式使用Base64.URL_SAFE.

So you could use Base64.URL_SAFE depending of the expected format of the string.

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