如何防止Volley请求重试? [英] How to prevent Volley request from retrying?
问题描述
我将JsonRequest发布到服务器.服务器速度很慢,Volley倾向于多次调用速度较慢的服务器,因为它没有收到第一个请求的响应(因为我的服务器速度很慢).有没有一种方法可以防止Volley重试请求,使其能够收到第一个响应?
I post a JsonRequest to a server. The server is slow and Volley tends to make multiple calls to the slow server because it didn't get a response from the first request (since my server is slow). Is there a way to prevent Volley from retrying a request so that it can receive the first response?
我尝试过:
myRequest.setRetryPolicy(new DefaultRetryPolicy(
TIMEOUT_MS,
RETRIES,
BACKOFF_MULT));
我已将TIMEOUT_MS替换为0,将RETRIES替换为0,并将BACKOFF_MULT替换为0,但是没有用.
I have replaced TIMEOUT_MS with 0, RETRIES with 0, and also BACKOFF_MULT with 0, but it didn't work.
有什么建议吗?
推荐答案
Volley默认重试策略为:
The Volley Default Retry Policy is:
/** The default socket timeout in milliseconds */
public static final int DEFAULT_TIMEOUT_MS = 2500;
/** The default number of retries */
public static final int DEFAULT_MAX_RETRIES = 1;
/** The default backoff multiplier */
public static final float DEFAULT_BACKOFF_MULT = 1f;
您可以在DefaultRetryPolicy.java中找到它,
You can find it in DefaultRetryPolicy.java,
因此您可以看到默认情况下齐射发出1个重试请求.
so you can see that volley makes 1 retry request by default.
尝试使用较小的TIMEOUT(如果您不想等待2500ms),或者使用大于2500ms的时间来获取答案),但请保留其他值,例如:
Try to use smaller TIMEOUT (if you don't want to wait the 2500ms), or bigger than 2500ms to get the answer), but keep the other values, for example:
// Wait 20 seconds and don't retry more than once
myRequest.setRetryPolicy(new DefaultRetryPolicy(
(int) TimeUnit.SECONDS.toMillis(20),
DefaultRetryPolicy.DEFAULT_MAX_RETRIES,
DefaultRetryPolicy.DEFAULT_BACKOFF_MULT));
因此,要禁止Volley重试,您需要执行以下操作:
Hence, to disable Volley from retrying you will need to do:
myRequest.setRetryPolicy(new DefaultRetryPolicy(
(int) TimeUnit.SECONDS.toMillis(20), //After the set time elapses the request will timeout
0,
DefaultRetryPolicy.DEFAULT_BACKOFF_MULT));
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