相当于"android:fontFamily =" sans-serif-light"在Java代码中? [英] What is the equivalent of "android:fontFamily="sans-serif-light" in Java code?

问题描述

我的问题很简单:

在我的每个textview中，我当前使用的是属性

In every of my textview, I am currently using the attribute

android:fontFamily="sans-serif-light"

在HC后设备上提供漂亮的外观.

to provide a gorgeous look on post HC devices.

不幸的是，这不适用于每个小部件，对于Spinners，我需要覆盖适配器.

Unfortunately, this doesn't work with every widget and for my Spinners, I need to overwrite the Adapter.

@Override
public View getView(int position, View convertView, ViewGroup parent) {
    //You can use the new tf here.

    if(convertView == null || convertView.getTag() == null) {
        // new view - populate 
        convertView = inflater.inflate(android.R.layout.simple_spinner_dropdown_item, parent, false);
        convertView.setTag(new Object());
    }

    CheckedTextView spinner_text=(CheckedTextView) convertView.findViewById(android.R.id.text1);
    //Typeface should be set here...
    return spinner_text;
    }
}

那么，有没有办法通过代码获得完全相同的结果?

So, is there a way to get exactly the same result by code?

PS:不，我不想在资产文件夹中放置字体，我只想使用系统一.

PS: No, I don't want to put a typeface in asset folder, I just want to use system one.

推荐答案

使用setTypeface()和Typeface.create()应该可以:

convertView.setTypeface(Typeface.create("sans-serif-light", Typeface.NORMAL));

请参见文档:

创建具有姓氏和选项样式的字体对象 信息.如果为该名称传递null，则使用默认"字体 将被选择.可以查询生成的字体对象 (getStyle())来发现其真实"样式特征是什么.

Create a typeface object given a family name, and option style information. If null is passed for the name, then the "default" font will be chosen. The resulting typeface object can be queried (getStyle()) to discover what its "real" style characteristics are.

请注意，如Typeface.create()对您的内存有害. >此评论. 建议的哈希表是一个很好的解决方案，但您有进行一些修改，因为您不是从资产中创建字体的.

Note that excessively using Typeface.create() is bad for your memory, as stated in this comment. The suggested Hashtable is a good solution, but you have to modify it a little since you don't create your typeface from an asset.

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