Twitter API获取推文-返回阻止的CORS源 [英] Twitter API get tweets - returns CORS origin blocked
问题描述
我正在尝试从主题标签获取推文.我收到以下错误跨域请求被阻止的消息:同源策略"不允许读取 https://api上的远程资源.twitter.com/oauth2/token . (原因:CORS标头"Access-Control-Allow-Origin"缺失). 跨域请求被阻止:相同来源策略不允许读取
I am trying to get tweets from a hashtag. I get following erros Cross-Origin Request Blocked: The Same Origin Policy disallows reading the remote resource at https://api.twitter.com/oauth2/token. (Reason: CORS header 'Access-Control-Allow-Origin' missing). Cross-Origin Request Blocked: The Same Origin Policy disallows reading the remote resource at https://api.twitter.com/1.1/search/tweets.json?f=tweets&q=%23shruthirajoli&src=typd?get=%5Bobject+Object%5D. (Reason: CORS header 'Access-Control-Allow-Origin' missing)
以下是我的代码: app.js
Below is my code: app.js
var app = angular.module('Twitter', ['ngResource']);
app.controller('TwitterCtrl', function($scope,$http,$resource){
// Create Base64 Object
var Base64={_keyStr:"ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/=",
encode:function(e){var t="";var n,r,i,s,o,u,a;var f=0;e=Base64._utf8_encode(e);while(f<e.length){n=e.charCodeAt(f++);r=e.charCodeAt(f++);i=e.charCodeAt(f++);s=n>>2;o=(n&3)<<4|r>>4;u=(r&15)<<2|i>>6;a=i&63;if(isNaN(r)){u=a=64}else if(isNaN(i)){a=64}t=t+this._keyStr.charAt(s)+this._keyStr.charAt(o)+this._keyStr.charAt(u)+this._keyStr.charAt(a)}return t},
decode:function(e){var t="";var n,r,i;var s,o,u,a;var f=0;e=e.replace(/[^A-Za-z0-9\+\/\=]/g,"");while(f<e.length){s=this._keyStr.indexOf(e.charAt(f++));o=this._keyStr.indexOf(e.charAt(f++));u=this._keyStr.indexOf(e.charAt(f++));a=this._keyStr.indexOf(e.charAt(f++));n=s<<2|o>>4;r=(o&15)<<4|u>>2;i=(u&3)<<6|a;t=t+String.fromCharCode(n);if(u!=64){t=t+String.fromCharCode(r)}if(a!=64){t=t+String.fromCharCode(i)}}t=Base64._utf8_decode(t);return t},_utf8_encode:function(e){e=e.replace(/\r\n/g,"\n");var t="";for(var n=0;n<e.length;n++){var r=e.charCodeAt(n);if(r<128){t+=String.fromCharCode(r)}else if(r>127&&r<2048){t+=String.fromCharCode(r>>6|192);t+=String.fromCharCode(r&63|128)}else{t+=String.fromCharCode(r>>12|224);t+=String.fromCharCode(r>>6&63|128);t+=String.fromCharCode(r&63|128)}}return t},_utf8_decode:function(e){var t="";var n=0;var r=c1=c2=0;while(n<e.length){r=e.charCodeAt(n);if(r<128){t+=String.fromCharCode(r);n++}else if(r>191&&r<224){c2=e.charCodeAt(n+1);t+=String.fromCharCode((r&31)<<6|c2&63);n+=2}else{c2=e.charCodeAt(n+1);c3=e.charCodeAt(n+2);t+=String.fromCharCode((r&15)<<12|(c2&63)<<6|c3&63);n+=3}}return t}}
var consumerKey = encodeURIComponent('');
var consumerSecret = encodeURIComponent('');
var credentials = Base64.encode(consumerKey + ':' + consumerSecret);
// Twitters OAuth service endpoint
var twitterOauthEndpoint = $http.post('https://api.twitter.com/oauth2/token', "grant_type=client_credentials"
, {headers: {'Authorization': 'Basic ' + credentials, 'Content-Type': 'application/x-www-form-urlencoded;charset=UTF-8'}});
twitterOauthEndpoint.success(function (response) {
// a successful response will return
// the "bearer" token which is registered
// to the $httpProvider
console.log(twitterOauthEndpoint );
app.$httpProvider.defaults.headers.common['Authorization'] = "Bearer " + response.access_token})
.error(function (response) {
// error handling to some meaningful extent
});
$scope.twitter = $resource('https://api.twitter.com/1.1/search/tweets.json?f=tweets&q=%23shruthirajoli&src=typd',
// {action: 'search.json', q:'angularjs', callback:'JSON_CALLBACK'},
{get:{method:'JSONP'}});
$scope.twitterResult = $scope.twitter.get();
});
app.config(function ($httpProvider) {
app.$httpProvider = $httpProvider
});
html
<!doctype html>
<html ng-app="Twitter">
<head>
<script src="http://code.angularjs.org/angular-1.0.0rc4.min.js"></script>
<script src="http://code.angularjs.org/angular-resource-1.0.0rc4.min.js"></script>
<script src="app.js"></script>
<link rel="stylesheet" href="http://twitter.github.com/bootstrap/1.4.0/bootstrap.min.css">
</head>
<body>
<div ng-controller="TwitterCtrl">
<table class="table table-striped">
<tr ng-repeat="tweet in twitterResult.results">
<td>{{tweet.text}}</td>
</tr>
</table>
</div>
</body>
</html>
我正在localhost:8000上运行此程序，我按照twisters的说明进行了故障排除.如果我有任何错误，可以让我知道.谢谢.
I am running this on localhost:8000, I followed twisters instructions to troubleshoot this. Can someone let me know, if I am making any mistake. thanks.
推荐答案
出现此错误的原因是因为您是通过浏览器发出请求的.浏览器不允许跨域请求，因为像在下面的注释中提到的@allenru一样:服务器需要根据CORS规范进行响应，以便浏览器可以继续进行请求.
The reason why you are getting this error is because your making the request through the browser. Browsers don't allow cross domain requests because like @allenru mentioned in the comments below: Servers need to response according to the CORS spec so the browser can proceed with the request.
您可以在这里了解更多信息: https://developer.mozilla.org/zh-CN/docs/Web/HTTP/Access_control_CORS
You can learn more about it here : https://developer.mozilla.org/en-US/docs/Web/HTTP/Access_control_CORS
获取推文的正确方法是致电服务器，并让服务器为您获取推文.
The proper way to fetch tweets would be making a call to the server and have the server fetch tweets for you.
这似乎也有错误.
https://api.twitter.com/1.1/search/tweets.json?f=tweets&q=%23shruthirajoli&src=typd?get=%5Bobject+Object%5D .
请求中包含[object + object]是不正常的.似乎没有对它进行字符串化处理.
This also seems like a buggy call.
https://api.twitter.com/1.1/search/tweets.json?f=tweets&q=%23shruthirajoli&src=typd?get=%5Bobject+Object%5D.
Its not normal to have [object + object] in requests. It seems like an object that was not stringified.
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