Angular UI路由，刷新后页面自动重定向到父状态 [英] Angular UI-Routing, Page automatically redirects to parent state when refreshed

问题描述

我正在一个使用Angular-UI路由的项目中工作.当我尝试刷新网页或直接输入URL时，它将被重定向到父状态.它确实加载了我已经重新加载的URL的状态，但是随后迅速重定向到了父状态.这是我的状态路由

I am working on a project in which I have used Angular-UI routing. When I try to refresh web page or enter URL directly, It is redirected to parent state. It does load the state of the URL which I have reloaded but then quickly redirects to parent state. Here is my state routing

$stateProvider
    .state('home', {
        url: "",
        views: {
            "home": {
                templateUrl: root_url + "home"
                },
            },
        })
    .state('home.store', {
        url: "/store",
        views: {
            "store": {
                templateUrl: root_url + "store"
                },
            },
        })
    .state('home.store.storecontent', {
        views: {
            "storecontent": {
                templateUrl: root_url + "storecontent"
                }
            }
        })

假设当前我处于home.store.storecontent状态.如果我在这里刷新页面，则在重载当前状态后，它将重定向到父状态(即home).我想避免这种情况.

Suppose currently I am on home.store.storecontent state. If I refreshed the page here, after reloading current state, It redirects me to the parent state which is home. I want to avoid this.

推荐答案

我们通常有两个选择.首先是为子级定义 url ，第二个是-生成父级抽象，这意味着该子级为默认.

We have two options in general. First is to define url for child, the second is - make parent abstract which will mean that it child is default.

有第一种方法的工作示例

如果我们希望不使父级"home.store"和子级"home.store.storecontent"抽象，则必须为它们两者定义唯一的网址，例如:

In case we would like to keep parent 'home.store' and child 'home.store.storecontent' non-abstract, we have to define unique url for both of them, e.g.:

.state('home.store', {
    url: "/store",
    ...
    })
.state('home.store.storecontent', {
    url: "/content",
    ...
    })

所以，现在我们有两个链接:

So, now we have two links:

<a href="#/store">
<a href="#/store/content">

每个人都会刷新唯一目标.在此处

对于第二种方法，有工作的矮人

如果要让 UI-Router 导航到"home.store"状态的子级，我们只需使其成为抽象.然后-如果有一个带有url: ""的 child -它将被用作要启动的非抽象状态.

In case, that we want UI-Router to navigate to a child of 'home.store' state, we just have to make it abstract. Then - if there is a child with url: "" - it will be used as a non abstract state to be initiated.

这些调整应执行以下操作:

These adjustment should do that:

.state('home.store', {
    url: "/store",
    // here, we make home.store to be abstract
    abstract: true,
    views: {
        "store": {
            templateUrl: root_url + "store"
            },
        },
    })
.state('home.store.storecontent', {
    // here, we say, that instead of parent (which url is selected)
    // this child state should be initiated
    url: "",
    views: {
        "storecontent": {
            templateUrl: root_url + "storecontent"
            }
        }
    })

检查它此处正在实施

如果'home.store'不应该是抽象的，我们应该给它的子对象提供一些非空的 url -区分这两个...

In case, that the 'home.store' should not be abstract, we should give some non empty url to its child - to distinguish these two...

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