使用骆驼数据库中的文件名读取文件内容 [英] Reading file content using file name from db in camel

问题描述

我必须在db中进行查询才能从表中获取文件名.然后，我必须使用从查询中获得的文件名来读取文件夹/目录中文件的内容.我已经完成了查询部分，并使用bean在Exchange中存储了文件名列表.但是我想知道如何使用此文件名来交换文件内容.你能帮忙吗?

I have to do a query in db to get the filenames from a table. And then I have to read the contents of files in a folder/directory using the file names I got from query. I have done the query part and stored the list of filenames in Exchange using a bean. But I am wondering how can I use this filenames in exchange to read the file contents. Could you please help?

推荐答案

您可以使用 Content Enricher (

You can use the pattern Content Enricher (http://camel.apache.org/content-enricher.html) and Camel 2.16 with dynamic endpoints to load the contents of a file, by path previously obtained from the database.

已更新

您必须使用 pollEnrich (因为 file 组件是 polling使用者)来使用uri中的文件，并且可以使用表达式(例如Simple)来配置fileName.

You have to use the pollEnrich (because file component is a polling consumer) to consume files from uri and you can use an expression (such as Simple) to configure the fileName.

您可以尝试类似的操作(仅适用于2.16以上的骆驼版本):

You can try something like that (only for Camel version greater than 2.16):

.pollEnrich("file:?fileName=${header.FILE_NAME}", 1000, new YourAggregationStrategy()) 

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