从Servlet访问WebContent文件夹中的文件 [英] Access file in WebContent folder from a servlet

问题描述

我正在尝试使用FOP生成PDF文档. pdf生成代码保存在servlet中，而xsl保存在WebContent文件夹中的特定文件夹中.

I'm trying to generate a PDF document using FOP. The pdf generation code is kept in a servlet and the xsl is in a specific folder in the WebContent folder.

如何通过给出相对路径来访问此xsl文件?仅当我在File对象中提供完整路径时，它才起作用.

How can I access this xsl file by giving a relative path? It works only if I give the complete path in the File object.

我需要动态生成xml内容.如何给动态生成的xml作为源而不是File对象?

I need to generate the xml content dynamically. How can I give this dynamically generated xml as the source instead of a File object?

请提供您的建议.

推荐答案

要获取路径，您可以执行以下操作:

To get the path you can just do:

String path = s.getServletContext().getRealPath("/WEB-INF/somedir/hdfeeh");         

s是实现HTTPServlet的类.如果this.getServletContext()是您的servlet类，您也可以使用this.getServletContext().

s is the class that implements HTTPServlet.You can also use this.getServletContext() if its your servlet class.

然后将其作为参数传递.

Then pass this as a parameter.

就使用动态生成的XML而言，您所使用的库应支持使用输入流，编写XML，将其转换为字节数组，然后将其包装在ByteArrayInputStream中并使用.

As far as using dynamically generated XML, the library you're using should support using an input stream, write your XML, convert it to a byte array, then wrap it in a ByteArrayInputStream and use this.

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