PySpark java.io.IOException:方案无文件系统:https [英] PySpark java.io.IOException: No FileSystem for scheme: https

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问题描述

我正在使用本地Windows,并尝试在python上使用以下代码加载XML文件,并且出现此错误,有人知道如何解决它,

I am using local windows and trying to load the XML file with the following code on python, and i am having this error, do anyone knows how to resolve it,

这是代码

df1 = sqlContext.read.format("xml").options(rowTag="IRS990EZ").load("https://irs-form-990.s3.amazonaws.com/201611339349202661_public.xml")

这是错误

Py4JJavaError                             Traceback (most recent call last)
<ipython-input-7-4832eb48a4aa> in <module>()
----> 1 df1 = sqlContext.read.format("xml").options(rowTag="IRS990EZ").load("https://irs-form-990.s3.amazonaws.com/201611339349202661_public.xml")

C:\SPARK_HOME\spark-2.2.0-bin-hadoop2.7\python\pyspark\sql\readwriter.py in load(self, path, format, schema, **options)
    157         self.options(**options)
    158         if isinstance(path, basestring):
--> 159             return self._df(self._jreader.load(path))
    160         elif path is not None:
    161             if type(path) != list:

C:\SPARK_HOME\spark-2.2.0-bin-hadoop2.7\python\lib\py4j-0.10.4-src.zip\py4j\java_gateway.py in __call__(self, *args)
   1131         answer = self.gateway_client.send_command(command)
   1132         return_value = get_return_value(
-> 1133             answer, self.gateway_client, self.target_id, self.name)
   1134 
   1135         for temp_arg in temp_args:

C:\SPARK_HOME\spark-2.2.0-bin-hadoop2.7\python\pyspark\sql\utils.py in deco(*a, **kw)
     61     def deco(*a, **kw):
     62         try:
---> 63             return f(*a, **kw)
     64         except py4j.protocol.Py4JJavaError as e:
     65             s = e.java_exception.toString()

C:\SPARK_HOME\spark-2.2.0-bin-hadoop2.7\python\lib\py4j-0.10.4-src.zip\py4j\protocol.py in get_return_value(answer, gateway_client, target_id, name)
    317                 raise Py4JJavaError(
    318                     "An error occurred while calling {0}{1}{2}.\n".
--> 319                     format(target_id, ".", name), value)
    320             else:
    321                 raise Py4JError(

Py4JJavaError: An error occurred while calling o38.load.
: java.io.IOException: No FileSystem for scheme: https
    at org.apache.hadoop.fs.FileSystem.getFileSystemClass(FileSystem.java:2660)
    at org.apache.hadoop.fs.FileSystem.createFileSystem(FileSystem.java:2667)
    at org.apache.hadoop.fs.FileSystem.access$200(FileSystem.java:94)
    at org.apache.hadoop.fs.FileSystem$Cache.getInternal(FileSystem.java:2703)
    at org.apache.hadoop.fs.FileSystem$Cache.get(FileSystem.java:2685)
    at org.apache.hadoop.fs.FileSystem.get(FileSystem.java:373)
    at org.apache.hadoop.fs.Path.getFileSystem(Path.java:295)
    at org.apache.hadoop.mapreduce.lib.input.FileInputFormat.setInputPaths(FileInputFormat.java:500)
    at org.apache.hadoop.mapreduce.lib.input.FileInputFormat.setInputPaths(FileInputFormat.java:469)
    at org.apache.spark.SparkContext$$anonfun$newAPIHadoopFile$2.apply(SparkContext.scala:1160)
    at org.apache.spark.SparkContext$$anonfun$newAPIHadoopFile$2.apply(SparkContext.scala:1148)
    at org.apache.spark.rdd.RDDOperationScope$.withScope(RDDOperationScope.scala:151)
    at org.apache.spark.rdd.RDDOperationScope$.withScope(RDDOperationScope.scala:112)
    at org.apache.spark.SparkContext.withScope(SparkContext.scala:701)
    at org.apache.spark.SparkContext.newAPIHadoopFile(SparkContext.scala:1148)
    at com.databricks.spark.xml.util.XmlFile$.withCharset(XmlFile.scala:46)
    at com.databricks.spark.xml.DefaultSource$$anonfun$createRelation$1.apply(DefaultSource.scala:62)
    at com.databricks.spark.xml.DefaultSource$$anonfun$createRelation$1.apply(DefaultSource.scala:62)
    at com.databricks.spark.xml.XmlRelation$$anonfun$1.apply(XmlRelation.scala:47)
    at com.databricks.spark.xml.XmlRelation$$anonfun$1.apply(XmlRelation.scala:46)
    at scala.Option.getOrElse(Option.scala:121)
    at com.databricks.spark.xml.XmlRelation.<init>(XmlRelation.scala:45)
    at com.databricks.spark.xml.DefaultSource.createRelation(DefaultSource.scala:65)
    at com.databricks.spark.xml.DefaultSource.createRelation(DefaultSource.scala:43)
    at org.apache.spark.sql.execution.datasources.DataSource.resolveRelation(DataSource.scala:306)
    at org.apache.spark.sql.DataFrameReader.load(DataFrameReader.scala:178)
    at org.apache.spark.sql.DataFrameReader.load(DataFrameReader.scala:156)
    at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
    at sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source)
    at sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source)
    at java.lang.reflect.Method.invoke(Unknown Source)
    at py4j.reflection.MethodInvoker.invoke(MethodInvoker.java:244)
    at py4j.reflection.ReflectionEngine.invoke(ReflectionEngine.java:357)
    at py4j.Gateway.invoke(Gateway.java:280)
    at py4j.commands.AbstractCommand.invokeMethod(AbstractCommand.java:132)
    at py4j.commands.CallCommand.execute(CallCommand.java:79)
    at py4j.GatewayConnection.run(GatewayConnection.java:214)
    at java.lang.Thread.run(Unknown Source)

推荐答案

以某种方式pyspark无法加载http或https,我的一位同事找到了答案,所以这里是解决方法,

Somehow pyspark is unable to load the http or https, one of my colleague found the answer for this so here is the solution,

在创建spark上下文和sql上下文之前,我们需要加载这两行代码

before creating the spark context and sql context we need to load this two line of code

import os
os.environ['PYSPARK_SUBMIT_ARGS'] = '--packages com.databricks:spark-xml_2.11:0.4.1 pyspark-shell'

sc = pyspark.SparkContext.getOrCreatesqlContext = SQLContext(sc)

使用sc.addFile(url)

Data_XMLFile = sqlContext.read.format("xml").options(rowTag="anytaghere").load(pyspark.SparkFiles.get("*_public.xml")).coalesce(10).cache()

此解决方案对我有用

这篇关于PySpark java.io.IOException:方案无文件系统:https的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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