Spark 2.0数据集groupByKey并对操作和类型安全进行划分 [英] Spark 2.0 DataSets groupByKey and divide operation and type safety

问题描述

我对Spark 2.0数据集感到非常满意，因为它具有编译时类型安全性.但是这里有几个我无法解决的问题，我也没有为此找到好的文档.

I am very much pleased with Spark 2.0 DataSets because of it's compile time type safety. But here is couple of problem that I am not able to work out, I also didn't find good documentation for this.

问题1-对汇总列进行除法运算- 考虑下面的代码- 我有一个DataSet [MyCaseClass]，我想在c1，c2，c3和sum(c4)/8上使用groupByKey.下面的代码可以很好地工作，如果我只是计算总和，但它会给出除法(8)的编译时错误.我不知道如何实现关注.

Problem #1 - divide operation on aggregated column- Consider below code - I have a DataSet[MyCaseClass] and I wanted to groupByKey on c1,c2,c3 and sum(c4) / 8. The below code works well if I just calculate the sum but it gives compile time error for divide(8). I wonder how I can achieve following.

final case class MyClass (c1: String,
                          c2: String,
                          c3: String,
                          c4: Double)

    val myCaseClass: DataSet[MyCaseClass] = ??? // assume it's being loaded

    import sparkSession.implicits._
    import org.apache.spark.sql.expressions.scalalang.typed.{sum => typedSum}

     myCaseClass.
       groupByKey(myCaseClass =>
          (myCaseClass.c1, myCaseClass.c2, myCaseClass.c3)).
          agg(typedSum[MyCaseClass](_.c4).name("sum(c4)").
          divide(8)). //this is breaking with exception
       show()

如果我删除.divide(8)操作并在命令上方运行，它将在输出下方显示.

If I remove .divide(8) operation and run above command it gives me below output.

+-----------+-------------+
|        key|sum(c4)      |
+-----------+-------------+
| [A1,F2,S1]|         80.0|
| [A1,F1,S1]|         40.0|  
+-----------+-------------+

问题2-将groupedByKey结果转换为另一个Typed DataFrame- 现在，我的问题的第二部分是我要再次输出类型化的DataSet.为此，我有另一个案例类(不确定是否需要)，但不确定如何与分组结果映射-

Problem #2 - converting groupedByKey result to another Typed DataFrame - Now second part of my problem is I want output again a typed DataSet. For that I have another case class (not sure if it is needed) but I am not sure how to map with grouped result -

final case class AnotherClass(c1: String,
                          c2: String,
                          c3: String,
                          average: Double) 

 myCaseClass.
           groupByKey(myCaseClass =>
              (myCaseClass.c1, myCaseClass.c2, myCaseClass.c3)).
              agg(typedSum[MyCaseClass](_.c4).name("sum(c4)")).
as[AnotherClass] //this is breaking with exception

但这又失败了，但有一个例外，因为按关键结果分组的结果没有直接与AnotherClass映射.

but this again fails with an exception as grouped by key result is not directly mapped with AnotherClass.

PS:实现上述目标的任何其他解决方案都非常受欢迎.

PS : any other solution to achieve above is more than welcome.

推荐答案

第一个问题可以通过完全使用类型化的列来解决(KeyValueGroupedDataset.agg期望TypedColumn(-s)) 您可以将聚合结果定义为:

The first problem can be resolved by using typed columns all the way down (KeyValueGroupedDataset.agg expects TypedColumn(-s)) You can defined aggregation result as:

val eight = lit(8.0)
  .as[Double]  // Not necessary

val sumByEight = typedSum[MyClass](_.c4)
  .divide(eight)
  .as[Double]  // Required
  .name("div(sum(c4), 8)")

并将其插入以下代码:

val myCaseClass = Seq(
  MyClass("a", "b", "c", 2.0),
  MyClass("a", "b", "c", 3.0)
).toDS

myCaseClass
  .groupByKey(myCaseClass => (myCaseClass.c1, myCaseClass.c2, myCaseClass.c3))
  .agg(sumByEight)

获得

+-------+---------------+
|    key|div(sum(c4), 8)|
+-------+---------------+
|[a,b,c]|          0.625|
+-------+---------------+

第二个问题是使用不符合数据形状的类的结果.正确的表示形式可能是:

The second problem is a result of using a class which doesn't conform to a data shape. A correct representation could be:

case class AnotherClass(key: (String, String, String), sum: Double)

用于上面定义的数据:

 myCaseClass
   .groupByKey(myCaseClass => (myCaseClass.c1, myCaseClass.c2, myCaseClass.c3))
   .agg(typedSum[MyClass](_.c4).name("sum"))
   .as[AnotherClass]

将给出:

+-------+---+
|    key|sum|
+-------+---+
|[a,b,c]|5.0|
+-------+---+

但是如果Dataset[((String, String, String), Double)]是可以接受的，则在这里不需要.as[AnotherClass].

but .as[AnotherClass] is not necessary here if Dataset[((String, String, String), Double)] is acceptable.

您当然可以跳过所有内容，而只需mapGroups(尽管并非不影响性能):

You can of course skip all of that and just mapGroups (although not without performance penalty):

import shapeless.syntax.std.tuple._   // A little bit of shapeless

val tuples = myCaseClass
 .groupByKey(myCaseClass => (myCaseClass.c1, myCaseClass.c2, myCaseClass.c3))
 .mapGroups((group, iter) => group :+ iter.map(_.c4).sum)

有结果

+---+---+---+---+   
| _1| _2| _3| _4|
+---+---+---+---+
|  a|  b|  c|5.0|
+---+---+---+---+

reduceGroups可能是一个更好的选择:

reduceGroups could be a better option:

myCaseClass
  .groupByKey(myCaseClass => (myCaseClass.c1, myCaseClass.c2, myCaseClass.c3))
  .reduceGroups((x, y) => x.copy(c4=x.c4 + y.c4))

，结果为Dataset:

+-------+-----------+    
|     _1|         _2|
+-------+-----------+
|[a,b,c]|[a,b,c,5.0]|
+-------+-----------+

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