如何将JSONObject发送到改造API调用android [英] how to send JSONObject into retrofit API call android

问题描述

我已经在我的android代码中实现了首次改造，并面临着以下问题

I have implemented first time retrofit in my android code and facing follwing issues

得到以下错误:java.lang.IllegalArgumentException:@Body参数不能与表单或多部分编码一起使用. (参数1)

getting following error : java.lang.IllegalArgumentException: @Body parameters cannot be used with form or multi-part encoding. (parameter #1)

我已经像下面那样实现了我的代码

I have implemented my code like below

public interface APIService {
@FormUrlEncoded
@POST("/")
@Headers({
        "domecode: axys",
        "Content-Type: application/json;charset=UTF-8"
})
 Call<JsonObject> sendLocation(@Body JsonObject jsonObject);
}


 public class ApiUtils {

static String tempUrl = "http://192.168.16.114:8092/api/v1/location/tsa/";
public static APIService getAPIService() {

    return RetrofitClient.getClient(tempUrl).create(APIService.class);
}

}

public class RetrofitClient{

private static Retrofit retrofit = null;

public static Retrofit getClient(String baseUrl){
    if(retrofit==null){
        retrofit = new Retrofit.Builder()
                .baseUrl(baseUrl)
                .addConverterFactory(GsonConverterFactory.create())
                .build();
    }
    return retrofit;
}

}

将值传递给API调用

           JsonObject postParam = new JsonObject();
            try {
                postParam.addProperty(Fields.ID, "asdf");
                }

 Call<JsonObject> call = apiService.sendLocation(postParam);
            call.enqueue(new Callback<JsonObject>() {
                             @Override
                             public void onResponse(Call<JsonObject> call, Response<JsonObject> response) {
                                 Log.d("response","Getting response from server : "+response);
                             }

                             @Override
                             public void onFailure(Call<JsonObject> call, Throwable t) {
                                 Log.d("response","Getting response from server : "+t);
                             }
                         }
            );

推荐答案

您正在使用Android内部的Json API.您需要改用Gson的类.

You are using the Android internal Json APIs. You need to use Gson's classes instead.

Call<JsonObject> sendLocation(@Body JsonObject jsonObject);

因此导入语句

import com.google.gson.JsonObject;

另一个错误是将回调作为参数传递给请求

Another error is passing the Callback as a parameter to the request

Call<JsonObject> call = apiService.sendLocation(jsonObject);
call.enqueue(new Callback<JsonObject>() {
   @Override
   public void onResponse(Call<JsonObject> call, Response<JsonObject> response) {
      Log.d("response","Getting response from server : "+response);
   }

   @Override
   public void onFailure(Call<JsonObject> call, Throwable t) {
      Log.d("response","Getting response from server : "+t);
   }
});

这篇关于如何将JSONObject发送到改造API调用android的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！