applicationWillEnterForeground呈现一个视图控制器 [英] applicationWillEnterForeground present a view controller

问题描述

我有一个PIN视图控制器，每次- (void)applicationWillEnterForeground:(UIApplication *)application触发时都需要显示.我有多个视图控制器，当应用程序进入后台时，用户可能在其中的任何一个上.

I have a PIN view controller which needs to be presented every time the - (void)applicationWillEnterForeground:(UIApplication *)application fires. I have multiple view controllers and when the app enters background the user could be on any of them.

问题是我不知道如何在当前处于活动状态的任何视图控制器上显示PIN视图控制器.这是我的实现的样子:

The problem is I don't know how to present the PIN view controller over any view controller that is currently active. Here's how my implementation looks:

- (void)applicationWillEnterForeground:(UIApplication *)application
{
    ResourceSingleton *resource = [ResourceSingleton sharedSingleton];
    if ([resource checkIfPINIsEnabled])
    {
        PinViewController *pinView = [[PinViewController alloc] initWithMode:kPINViewControllerModeEnter];
        pinView.modalTransitionStyle = UIModalTransitionStyleCrossDissolve;
        [self.window.rootViewController presentViewController:pinView animated:YES completion:NULL];
    }
}

但是只有当我在第一个视图控制器(根目录控制器)上时，才会显示PIN视图.如何在任何视图控制器上弹出它?

But the PIN view appears only if I'm at the first view controller (the root one). How to pop it up on any view controller?

我已经看到使用applicationwillenterforeground作为密码屏幕，但是必须是更好的方法还是我错了?这将适用于iOS 7，因此，如果只有7具有这样的功能就可以了，但是我很确定它也可以在6上完成.

I have seen Using applicationwillenterforeground for a passcode screen but there has to be a better way or am I wrong? This will be for iOS 7 so if only 7 has such a functionality its ok but I am pretty sure it can be done on 6 as well.

推荐答案

您可以让应用程序委托处理PIN视图的逻辑，并将其作为视图而不是视图控制器.只需将视图添加为窗口的子视图，它就会显示在其他任何地方.

You could have the app delegate handle the logic for the PIN view, and have that be a view, rather than a view controller. Just add the view as a subview of the window, and it will be shown over anything else.

- (void)applicationWillEnterForeground:(UIApplication *)application {
    UINib *pinNib = [UINib nibWithNibName:@"PINView" bundle:nil];
    UIView *pinView = [pinNib instantiateWithOwner:self options:nil][0];
    [self.window addSubview:pinView];
}

如果使应用程序委托为xib的文件所有者，则可以将视图中需要的所有出口连接到应用程序委托.

If you make the app delegate the File's Owner of the xib, then you can hook up any outlets you need in the view to the app delegate.

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