下面的C代码显示:格式'%s'期望类型为'char *'的参数,但是参数3的类型为int [英] The following C code shows that : format '%s' expects argument of type 'char *', but argument 3 has type int

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问题描述

以下代码显示格式'%s'期望类型为'char *'的参数,但第139行的类型为'int'.我看不到变量类型有任何错误.在scanf上存在此问题.除了这个问题,还有3个相关的问题.我一直在尝试并得到同样的错误.我问是否有人可以帮忙?

The following code shows that format '%s' expects argument of type 'char *', but line 139 has type 'int'. I don't see any mistakes in variable types. This issue is present at the scanf. Along with this issue there are 3 more related ones. I keep trying and getting this very same error. I ask if someone can please kindly assist?

这是结构:

struct employee
    {
            char name[50];
            char sex;
            char adrs[50];
            char dsgn[25];
            int age,empID;
            float slry;
    };

这是完整的代码:

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <conio.h>
#include <ctype.h>
#include <stdbool.h>
#include <windows.h>
#include "struct.h"

void insert();
void list();
void edit();
void del();
void ext();

FILE * fptr, *ftemp;
struct employee e;
long int recsize;
char empname[50];



int main()
{
    //FILE * fptr, *ft;
    int choice;
    //fptr = fopen("ems.txt","rb+");

    fptr = fopen("ems.txt", "r+");


    if (fptr == NULL)
    {
        printf("Can't find file! Attempting to create file... \n");

        fptr = fopen("ems.txt","w+");
        if(fptr == NULL)
        {
            printf("Can't create file. Exiting...");
         ext(1);
        }
    }

    //Explain the reason for this?
    //recsize = (long int) sizeof(e);//


    while(1)
    {
        printf("*******************************\n");
        printf("\nEmployee management system");
        printf("\n1. Insert employee information");
        printf("\n2. List all employee information");
        printf("\n3. Edit employee information");
        printf("\n4. Delete employee information");
        printf("\n5. Exit");
        printf("\n\n*****************************\n");
        printf("\n\n Enter your choice: ");
        scanf("%d", &choice);
        fflush(stdin);

        switch(choice)
        {
            case 1:
                puts("Insert was chosen");
                insert();

                break;
            case 2:
                puts("List was chosen");
                list();
                break;
            case 3:
                puts("Edit was chosen");
                edit();
                break;
            case 4:
                puts("Delete was chosen");
                del();
                break;
            case 5:
                puts("Exit was chosen");
                ext(1);
                break;
            default:
                puts("Choice is incorrect!!");
                continue;
        }
    }

    return 0;
}


void insert()
{
    char next;

    do
    {
        printf("********************************************************** \n");
        printf("\nEnter the name of the employee: ");
        gets(e.name);
        printf("\nEnter the sex of the employee (M/m or F/f): ");
        gets(&e.sex);
        printf("\nEnter the address of the employee: ");
        gets(e.adrs);
        printf("\nEnter designation of the employee: ");
        gets(e.dsgn);
        printf("\nEnter age of the employee: ");
        scanf("%d", &e.age);
        printf("\nEnter basic salary of the employee: ");
        scanf("%f", &e.slry);
        printf("\nEnter the employee's ID: ");
        scanf("%d", &e.empID);
        fputs(e.name, fptr);
        fputs(&e.sex, fptr);
        fputs(e.adrs, fptr);
        fputs(e.dsgn, fptr);
        fprintf(fptr, "%d \n%f \n%d \n", e.age, e.slry, e.empID);
       // fwrite(&e,recsize,1,fptr);
        fflush(stdin);
        printf("\nDo you want to input more? (y/n): ");
        next = getche();
        printf("\n");


    }
    while(next !='n');

    fclose(fptr);
}

void list ()
{
    /* what is going on here??? */
    while(fread(&e,recsize,1,fptr)==1)
    {
        printf("\n%s %s %s %s %d %.2f %d",e.name,e.sex,e.adrs,e.dsgn,e.age,e.slry,e.empID);
    }

    getche();
    return ;
}

void edit ()
{
    char next;
    do
    {
        printf("Enter the employee name to be edited: ");
        scanf("%s", empname);
        while(fread(&e,recsize,1,fptr)==1)
        {
            if(strcmp(e.name,empname) == 0)
            {
                printf("\nEnter new name,sex,address,designation,age,salary,employee ID ");
                scanf("%s %s %s %s %d %.2f %d",e.name,e.sex,e.adrs,e.dsgn,&e.age,&e.slry,&e.empID);
                fseek(fptr,-recsize,SEEK_CUR);
                fwrite(&e,recsize,1,fptr);
                break;
            }
        }
        printf("\nEdit another record(y/n)");
        next = getche();
        fflush(stdin);

    }
    while(next != 'n');


    return ;
}

void del()
{
    char next;
    do
    {
        printf("\nEnter name of employee to delete: ");
        scanf("%s",empname);
        ftemp = fopen("Temp.dat","wb");
        while(fread(&e,recsize,1,fptr) == 1)
        {
            if(strcmp(e.name,empname) != 0)
            {
                fwrite(&e,recsize,1,ftemp);
            }
        }

        fclose(fptr);
        fclose(ftemp);
        remove("ems.txt");
        rename("Temp.dat","ems.txt");
        fptr = fopen("ems.txt", "rb+");
        printf("Delete another record(y/n)");
        fflush(stdin);
        next = getche();


    }while(next !='n');
}

推荐答案

您没有正确遵循格式,即:在打印使用%s的字符时,例如:在这里printf("\n%s %s %s %s %d %.2f %d",e.name,e.sex,e.adrs,e.dsgn,e.age,e.slry,e.empID);您正在使用%s因为e.sex只是一个字符. 并使用%s多次通过scanf接受像e.sex这样的char输入,如下所示:scanf("%s %s %s %s %d %.2f %d",e.name,e.sex,e.adrs,e.dsgn,&e.age,&e.slry,&e.empID);,请改用%c. 修正这些格式,同时以格式化的方式获取输入和打印输出,请参见.

You are not following the format properly, ie: while printing a character you are using %s, like: here printf("\n%s %s %s %s %d %.2f %d",e.name,e.sex,e.adrs,e.dsgn,e.age,e.slry,e.empID); you are using %s for e.sex which is merely a character. And used %s for taking char inputs like e.sex via scanf several times, like this: scanf("%s %s %s %s %d %.2f %d",e.name,e.sex,e.adrs,e.dsgn,&e.age,&e.slry,&e.empID);, use %c instead. Fix these formatting both while taking input and printing output in a formatted way and see.

您可以从 printf手册页

You can take help from printf man page and scanf man page for details.

这篇关于下面的C代码显示:格式'%s'期望类型为'char *'的参数,但是参数3的类型为int的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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