如何根据重要成分搜索配方? Java Android [英] how to search recipe based on important ingredients ? java android

问题描述

我想搜索与购物清单项目匹配的食谱，它会根据香蕉奶昔{牛奶和香蕉}中最重要的成分向用户建议食谱，如果我可以单独使用香蕉奶昔{糖和香草}的话，在购物清单上添加{banana，milk}之类的商品，它将根据这些成分而不是{banana，milk，糖和香草}搜索食谱 例如:

I want to search recipe which match with shopping list items and it will suggest recipe to user based on most important ingredients like in Banana MilkShake {milk and banana} could make banana milkshake alone {sugar and vanilla} are optional,if I add items on shopping list like {banana,milk} it will search recipe on the basis of these ingredients rather {banana,milk,sugar and vanilla} for example:

Banana Milk Shake Ingredients:

**Ingredient Name                
  1.banana                         (important)
  2.milk                           (important)
  3.vanilla                        (optional/not important)
  4.sugar                          (optional/not important) 

**Shopping List**

• 香蕉
• 牛奶
• 鸡蛋
• 米饭
• banana
• milk
• egg
• rice

我们还可以制作不含糖和香草的香蕉奶昔，因此重要的成分将是牛奶和香蕉.

We could also make Banana Milkshake without sugar and vanilla so important ingredients will be milk and banana.

public class Ingredient implements Serializable{

    private String name;
    private String quantity;

    public  Ingredient(){

    }

    public Ingredient(String name,String quantity){
        this.name=name;
        this.quantity=quantity;
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    @Override
    public String toString() {
        return name;
    }

    public String getQuantity() {
        return quantity;
    }

    public void setQuantity(String quantity) {
        this.quantity = quantity;
    }

}

和我的工作代码:

public Set<Recipe> searchByIngredient(List<ShoppingList> shop, List<Recipe> list) {
     int matchedItems = 0;
     Set<Recipe> result = new HashSet<Recipe>();
     for (Recipe rn : list) {
          boolean recipeMatched = false;

          for (ShoppingList r : shop) {

               for (int i = 0; i < rn.getIngre().size(); i++) {
                    if (rn.getIng(i).contains(r.getName())) {
                        matchedItems++;

                        int temp = matchedItems;

                        if(temp >= 2){
                            result.add(rn);
                            recipeMatched = true;
                        }

                    }
                    if (recipeMatched)
                        break;
               }

               if (recipeMatched)
                    break;
          }
          matchedItems = 0;
     }
     return result;
}

public class Recipe implements Serializable{

    private  String instructions;
    private String recName;
    private String image;
    private List<Ingredient> ing = new ArrayList<Ingredient>();

    public Recipe(){

    }
    public Recipe(String item,String quan){
        this.ing.add(new Ingredient(item, quan));
    }


    public List<Ingredient> getIngre(){
        return ing;
    }
    public String getIng(int i){

        return ing.get(i).toString();
    }
    public void setIngredients(List<Ingredient> item){
        this.ing = item;
    }

    public String getRecName() {
        return recName;
    }

    public void setRecName(String recName) {
        this.recName = recName;
    }

    // @Override
    public String toString() {
        return recName;
    }

    public String getInstructions() {
        return instructions;
    }

    public void setInstructions(String instructions) {
        this.instructions = instructions;
    }

    public String getImage() {
        return image;
    }

    public void setImage(String image) {
        this.image = image;
    }
}

推荐答案

根据您的评论.您可以向您的成分类添加另一个变量.像这样:

Based on your comments. You could add another variable to your Ingredient class. Like this:

public class Ingredient implements Serializable{

    private String name;
    private String quantity;
    private boolean isImportant;

    public  Ingredient(){

    }

    public Ingredient(String name,String quantity){
        this.name=name;
        this.quantity=quantity;
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    @Override
    public String toString() {
        return name;
    }

    public String getQuantity() {
        return quantity;
    }

    public void setQuantity(String quantity) {
        this.quantity = quantity;
    }

    public boolean getIsImportant() {
        return isImportant;
    }

    public void setIsImportant(boolean isImportant) {
        this.isImportant= isImportant;
    }

}

然后，您可以检查食谱中是否存在所有重要成分.

Then you could check in the recipe if all the important ingredients are present or not.

这篇关于如何根据重要成分搜索配方? Java Android的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！