从函数返回数组 [英] Returning an array from a function

问题描述

这是我的代码

double hour_payload_add(int entries , double array[])
{
    int index=0 ,k=0;
    int totalpayload=0;
    double returnarray[entries/120];
    while(k< entries)
    {
           totalpayload = totalpayload + array[k];
            if(k%120==0)
                {
                returnarray[index] = totalpayload;
                index++;
                totalpayload=0;
                }

    }

return returnarray;
}

在这里我叫它

double hourgraph[hrentries];
 hourgraph= hour_payload_add(entries , graph);

当我想返回数组时，不使用指针该怎么做才能返回?

as I want to return an array what should I do to return without using pointers?

推荐答案

通过引用将数组传递给函数，并且不返回任何内容.小例子:

Pass the array by reference to the function and don't return anything. Small example:

void hour_payload_add(int entries , double array[], double (&returnArray)[SIZE])
{
  // returnArray will be updated as it's external to function.
}

或

void hour_payload_add(int entries , double array[], double *returnArray) // <-- pointer
{
  // returnArray will be updated as it's external to function.
}

用法:

double returnArray[SIZE];
hour_payload_add(entries, array, returnArray);

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