从数组javascript中删除元素(相反的交集) [英] removes elements from array javascript (contrary intersection)

问题描述

昨天，我提出了这个问题从数组javascript中删除元素 但是我误解了，我的解释和示例都是关于两个数组之间的交集.
我想问的是如何删除数组中其他数组中不存在的元素.
示例:

Yesterday nigth I maked this question Delete elements from array javascript But I mistook, my explanation and my example were about an intersection between two arrays.
What I wanted to ask is about how remove elements on array that doesn´t exist on other array.
Example:

Array A=> [a, b, c, d]  
Array B=> [b, d, e]  
Array C= removeElementsNotIn(A, B);  
Array C (after function)-> [a,c]

非常感谢您.

推荐答案

您可以使用.filter()有选择地删除未通过测试的项目.

You can use .filter() to selectively remove items that don't pass a test.

var c = a.filter(function(item) { 
    return b.indexOf(item) < 0; // Returns true for items not found in b.
});

在函数中:

function removeElementsNotIn(a, b) {
    return a.filter(function(item) { 
       return b.indexOf(item) < 0; // Returns true for items not found in b.
    });
}
var arrayC = removeElementsNotIn(arrayA, arrayB);

如果您想真正(仅高级)，可以创建一个返回过滤功能的函数，如下所示:

If you want to get really fancy (advanced only), you can create a function that returns the filtering function, like so:

function notIn(array) {
    return function(item) {
        return array.indexOf(item) < 0;
    };
}
// notIn(arrayB) returns the filter function.
var c = arrayA.filter(notIn(arrayB)); 

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