如何使用存储库模式将两个实体保存在一起 [英] How to save two entities together using a repository pattern
本文介绍了如何使用存储库模式将两个实体保存在一起的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
这是我的IGenericRepository
public interface IGenericRepository<T>
{
IEnumerable<T> GetAll();
IEnumerable<T> GetMany(Func<T, bool> predicate);
void Insert(T obj);
void Save();
}
这是它的实现
public class GenericRepository<T> : IGenericRepository<T> where T : class
{
private ApplicationDbContext db;
private DbSet<T> table = null;
public GenericRepository(ApplicationDbContext db)
{
this.db = db;
table = db.Set<T>();
}
public IEnumerable<T> GetAll()
{
return table.ToList();
}
public IEnumerable<T> GetMany(Func<T, bool> predicate)
{
var data=table.Where(predicate);
return data;
}
public void Insert(T obj)
{
table.Add(obj);
}
public void Save()
{
db.SaveChanges();
}
}
这是Department
public interface IDepartmentRepository : IGenericRepository<Department>
{
IEnumerable<Department> GetAlldepartment();
void Save1();
}
public class DepartmentRepository : GenericRepository<Department>, IDepartmentRepository
{
private ApplicationDbContext db;
public DepartmentRepository(ApplicationDbContext db):base(db)
{
this.db = db;
}
public IEnumerable<Department> GetAlldepartment()
{
var v= from c in db.Departments
select c;
return v;
}
public void Save1()
{
db.SaveChanges();
}
}
同样,我还有一个用于Customer
As same I have another repository for Customer
public interface ICustomerRepository : IGenericRepository<Customer>
{
IEnumerable<Customer> SelectAll();
void Update(Customer obj);
void Delete(string id);
}
public class CustomerRepository : GenericRepository<Customer>, ICustomerRepository
{
private ApplicationDbContext db;
//public CustomerRepository()
//{
// this.db = new ApplicationDbContext();
//}
public CustomerRepository(ApplicationDbContext db)
: base(db)
{
this.db = db;
}
public IEnumerable<Customer> SelectAll()
{
var data = this.GetMany(a => a.Id == 1);
return data;
}
public void Update(Customer obj)
{
db.Entry(obj).State = EntityState.Modified;
}
public void Delete(string id)
{
Customer existing = db.Customers.Find(id);
db.Customers.Remove(existing);
}
}
最后我的控制器是
public class DepartmentController : Controller
{
DepartmentRepository _departmentRepository=null;
ICustomerRepository _customerRepository=null;
ApplicationDbContext _context = new ApplicationDbContext();
public DepartmentController()
{
this._departmentRepository = new DepartmentRepository(_context);
this._customerRepository = new CustomerRepository(_context);
}
public ActionResult Index()
{
var data = _departmentRepository.GetAlldepartment();
return View(data);
}
public ActionResult Create()
{
return View();
}
[HttpPost]
public ActionResult Create(Department Department)
{
_departmentRepository.Insert(Department);
List<Customer> list = new List<Customer>();
for (int i = 0; i < 5; i++)
{
list.Add(new Customer
{
Id = i,
Name = i + " Hi"
});
_customerRepository.Insert(list[i]);
}
_departmentRepository.Save();
return RedirectToAction("Index");
}
protected override void Dispose(bool disposing)
{
base.Dispose(disposing);
}
}
如果要从DepartmentController
保存Department
和Customer
,则只需创建DBcontext
对象的实例,然后将同一对象传递给两个存储库类.有什么问题吗?如果是这样,请帮助我该怎么做.
If I want to save Department
and Customer
from DepartmentController
, then I just create an instance of my DBcontext
object and pass same object to both repository classes. Is there any problem? If so please help me how I can do this.
推荐答案
在ActionFilter中创建一个TransactionScope并将其放在您的控制器操作上
Create a TransactionScope in an ActionFilter and put it on your controller action
[AttributeUsage(AttributeTargets.Method)]
public class TransactionScopeAttribute : ActionFilterAttribute
{
private TransactionScope TransactionScope { get; set; }
public override void OnActionExecuting(ActionExecutingContext filterContext)
{
TransactionScope =
new TransactionScope(TransactionScopeOption.Required, new TransactionOptions
{
IsolationLevel = System.Transactions.IsolationLevel.ReadCommitted
});
}
public override void OnActionExecuted(ActionExecutedContext filterContext)
{
if (TransactionScope == null)
return;
if (filterContext.Exception == null)
{
TransactionScope.Complete();
return;
}
TransactionScope.Dispose();
}
}
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