在32位保护模式/MSVC内联汇编中获取FS:[0]的线性地址 [英] Get linear address of FS:[0] in 32-bit protected mode / MSVC inline asm

问题描述

我在Visual C ++内联汇编中使用了此指令

I used this instruction in Visual C++ inline assembly

lea eax, FS:[0]

为什么eax变为零?

如何获取FS:[0]的线性地址?

推荐答案

假定FS指向Windows 线程信息块(TIB)，也称为线程环境块(TEB)，您可以通过读取fs:[0x18]处的32位值来获得TIB的线性地址.在Visual C ++中执行此操作的最佳方法是使用 __readfsdword 内部的:

Assuming FS points to the Windows Thread Information Block (TIB), also known as the Thread Environment Block (TEB), you get the linear address of the TIB by reading the 32-bit value at fs:[0x18]. The best way to do this in Visual C++ is to use the __readfsdword intrinsic:

TEB *teb = (TEB *) __readfsdword(0x18);

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