在R中分配一个字符串名称为data.frame的列 [英] Assign a column of a data.frame with string name in R

问题描述

我正在尝试使用循环中生成的名称将数据分配给现有数据框.一个基本的例子可能是

I am trying to assign data to an existing dataframe with a name generated in a loop. A basic example might be

A = data.frame(a = c(1,2,3), b=c(3,6,2))

for (i in 1:2){
    name = paste("Name",i, sep="")
    assign(name, c(6,3,2))
}

现在，我只需要弄清楚如何在data.frame A中添加name1和name2，同时保留它们的分配名称.我敢肯定有一个简单的答案，我只是现在还没有看到.

Now I just need to figure out how to add name1 and name2 to the data.frame A, while keeping their assigned name. I'm sure there is an easy answer, I'm just not seeing it right now.

最后我想结束

A
#a b name1 name2
#1 3 6      6
#2 6 3      3
#3 2 2      2

但是我需要以自动化的方式进行.

But I need to do this in an automated fashion.

例如，如果可以将for循环修改为

For instance if the for loop could be adapted to be like

for (i in 1:2){
    name = paste("Name",i, sep="")
    assign(name, c(6,3,2)
    A= cbind(A, get(paste(name,i,sep="")))  # works but doesn't maintain the column name as name1 or name2 etc
}

但这不会保留列名

推荐答案

其他答案也不错，但是，如果您像使用循环那样设置循环，那么它将起作用:

The other answers are good, but if you are set on using a loop like you have, then this would work:

A <- data.frame(a = c(1,2,3), b = c(3,6,2))

for (i in 1:2){
    A[paste("Name", i, sep="")] <- c(6,3,2)
}

给出

> A
  a b Name1 Name2
1 1 3     6     6
2 2 6     3     3
3 3 2     2     2

或者，可以将paste("Name", i, sep="")替换为paste0("Name", i)

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