从Wav文件中删除秒的前.5 [英] Remove the first .5 of a second from Wav file

问题描述

如何从Wav文件中删除秒的前.5?

How can I remove the first .5 of a second from Wav file?

推荐答案

此处为格式.您需要打开文件，找到标题的大小，然后删除所需数量的样本.您可以在标题中找到每个样本的位数.一个16位WAV文件(采样率为44100 Hz)将要求您删除(16/8) * 44100 * 0.5 = 44100 bytes

Here is the format. You need to open up the file, find the size of the header, then remove the required number of samples. You can find the number of bits per sample in the header. A 16-bit WAV file at a sampling rate of 44100 Hz would require you to remove (16/8) * 44100 * 0.5 = 44100 bytes

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