AutoIt GUICtrl读取特殊字符 [英] AutoIt GUICtrlRead Specials characters

问题描述

autoit GUICtrlCreateInput特殊字符被忽略了吗?

autoit GUICtrlCreateInput special char ignored ?

$user = GUICtrlCreateInput("", 90, 65, 100, 20)
$dom = GUICtrlCreateInput("", 90, 95, 100, 20)
$pass = GUICtrlCreateInput("", 90, 125, 100, 20, 0x0020)

Send(GUICtrlRead($user) & "{tab}" & GUICtrlRead($dom) & "{tab}" & GUICtrlRead($pass) & "{Enter}")

示例:"TOTO"作为用户，"home"作为dom，"azerty +"作为密码. 输出将是:

Example with : "TOTO" as user, "home" as dom and, "azerty+" as password. Output will be :

TOTO    home    azerty

为什么GUICtrlRead()忽略特殊字符作为我的"+"字符?

Why GUICtrlRead() ignore specials characters as my "+" char ?

如何修复?

推荐答案

来自帮助文件:

发送() 将模拟的击键发送到活动窗口.

Send() Sends simulated keystrokes to the active window.

发送(键" [，标志])

Send ( "keys" [, flag] )

参数

• 密钥-要发送的密钥序列.
• 标志[可选] -更改键"的处理方式:标志= 0 (默认)，文本包含特殊字符，例如+和！以表示 SHIFT和ALT键按下. flag = 1，密钥是原始发送的.

• keys - The sequence of keys to send.
• flag [optional] - Changes how "keys" is processed: flag = 0 (default), Text contains special characters like + and ! to indicate SHIFT and ALT key-presses. flag = 1, keys are sent raw.

因此，您的示例缺少设置为1的标志.

So, your example is missing flag set to 1.

$user = GUICtrlCreateInput("", 90, 65, 100, 20)
$dom = GUICtrlCreateInput("", 90, 95, 100, 20)
$pass = GUICtrlCreateInput("", 90, 125, 100, 20, 0x0020)

Send(GUICtrlRead($user),1)
Send("{tab}")
Send(GUICtrlRead($dom),1)
Send("{tab}")
Send(GUICtrlRead($pass),1)
Send("{Enter}")

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