Sed:获取以某些前缀开头的行 [英] Sed: get lines beginning with some prefix

问题描述

我有Blackberry jad文件:

I have file Blackberry jad file:

RIM-COD-URL-12: HelloWorld-12.cod
RIM-COD-Size: 68020
RIM-MIDlet-Icon-2-1: ____HOVER_ICON_res/icon/blackberry/icon-68.png,focused
RIM-COD-URL-11: HelloWorld-11.cod
RIM-MIDlet-Icon-Count-2: 1
RIM-COD-URL-10: HelloWorld-10.cod
RIM-MIDlet-Icon-Count-1: 1
MIDlet-Vendor: Vasia Pupkin
RIM-MIDlet-Icon-1-1: res\icon\blackberry\____HOVER_ICON_icon-68.png,focused
Manifest-Version: 1.0
RIM-MIDlet-Flags-1: 0
RIM-COD-SHA1-38: 9a c8 b3 35 72 de 34 5e 7a 0a 5b 9e c3 3a 65 4c 20 0f 8e 50

我只想让行以RIM-COD-开头.

可以为我提供awk或sed的解决方案吗?

Can you provide me solutions for awk or sed?

推荐答案

使用sed -n，仅打印与RIM-COD匹配的行.

Use sed -n and only print lines that match RIM-COD.

sed -n -e '/^RIM-COD-/p' yourfile.txt

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