在awk中的反斜杠("\")定界符上分割字符串? [英] Split string on a backslash ("\") delimiter in awk?

问题描述

我正在尝试基于某些定界符将字符串拆分到文件中.但是我无法正确实现它.这是下面的代码.

I am trying to split the string in a file based on some delimiter.But I am not able to achieve it correctly... Here is my code below.

awk 'var=split($2,arr,'\'); {print $var}' file1.dat

这是我的样本数据专家.

Here is my sample data guys.

Col1 Col2
abc  123\abc
abcd 123\abcd

期望输出:

Col1 Col2
abc  abc
abcd abcd

推荐答案

样本数据和输出是我对您要求的最佳猜测

Sample data and output is my best guess at your requirement

 echo '1:2\\a\\b:3' | awk -F: '{ 
     n=split($2,arr,"\\")
     # print "#dbg:n=" n
     var=arr[3]
     print var
     }'

输出

b

回想一下split返回它发现要拆分的字段数.您可以取消注释调试行，然后将看到返回值3.

Recall that split returns the number of fields that it found to split. You can uncomment the debug line and you'll see the value 3 returned.

还请注意，对于我的测试，我必须使用2个'\'字符来处理1个字符.我认为您不需要在文件中使用它，但是如果这不适用于文件，请尝试根据需要在数据中添加额外的"\".我尝试了几种使用'\'的变体，这似乎是最简单的.欢迎其他人发表评论！

Note also that for my test, I had to use 2 '\' chars for 1 to be processed. I don't think you'll need that in a file, but if this doesn't work with a file, then try adding extra '\' as needed to your data. I tried several variations on how to use '\', and this seems the most straightforward. Others are welcome to comment!

我希望这会有所帮助.

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