将第二个模式转换为awk中的毫秒 [英] Converting second pattern to millisecond in awk

问题描述

我有一个文件，文件中包含模式"s"，我需要乘以1000转换为"ms".我无法执行此操作.请帮助我.

I have file which is having pattern 's' , I need to convert into 'ms' by multiplying by 1000. I am unable to do it. Please help me.

file.txt

First launch 1
App: +1s170ms

First launch 2
App: +186ms

First launch 3
App: +1s171ms

First launch 4
App: +1s484ms

First launch 5
App: +1s227ms

First launch 6
App: +204ms

First launch 7
App: +1s180ms

First launch 8
App: +1s177ms

First launch 9
App: +1s183ms

First launch 10
App: +1s155ms

我的代码:

awk 'BEGIN { FS="[: ]+"}
/:/ && $2 ~/ms$/{vals[$1]=vals[$1] OFS $2+0;next}
END {
         for (key in vals)
          print key vals[key]
}' file.txt

预期输出:

App 1170 186 1171 1484 1227 204 1180 1177 1183 1155

即将到来的输出

App 1 186 1 1 1 204 1 1 1 1

如果出现第二种模式，如何将上述模式s转换为"ms".

How to convert in above pattern 's' to 'ms' if second pattern comes .

推荐答案

在这里我将尝试做一些解释，然后将其应用于您的情况.

What I will try to do here is explain it a bit generic and then apply it to your case.

问题:我有一个字符串，格式为123a456b7c8d，其中数字是任意长度的数字整数值，字母是相应的单位.我还具有将单位a,b,c,d转换为单位f的转换因子.如何将其转换为单一数量的f单位?

Question: I have a string of the form 123a456b7c8d where the numbers are numeric integral values of any length and the letters are corresponding units. I also have conversion factors to convert from unit a,b,c,d to unit f. How can I convert this to a single quantity of unit f?

示例:从1s183ms到1183ms

策略:

1. 为每个字符串创建一组键值对'a' => 123，'b' => 456，'c' => 7和'd' => 8
2. 将每个值乘以corect转换因子
3. 将数字加在一起

1. create per string a set of key-value pairs 'a' => 123,'b' => 456, 'c' => 7 and 'd' => 8
2. multiply each value with the corect conversion factor
3. add the numbers together

假设我们使用awk，并且键值对存储在数组a中，并且键作为索引.

Assume we use awk and the key-value pairs are stored in array a with the key as an index.

1. 从str提取键值对:

function extract(str,a,   t,k,v) {
   delete a; t=str; 
   while(t!="") { 
      v=t+0; match(t,/[a-zA-Z]+/); k=substr(t,RSTART,RLENGTH);
      t=substr(t,RSTART+RLENGTH);
      a[k]=v
   }
   return
 }

转换和求和:这里我们假设我们有一个数组f，其中包含转换因子:

convert and sum: here we assume we have an array f which contains the conversion factors:

function convert(a,f,  t,k) {
   t=0; for(k in a) t+=a[k] * f[k]
   return t
}

完整代码(以OP为例)

The full code (for the example of the OP)

# set conversion factors
BEGIN{ f['s']=1000; f['ms'] = 1 }
# print first word
BEGIN{ printf "App:" }
# extract string and print
/^App/ { extract($2,a); printf OFS "%dms", convert(a,f) }
END { printf ORS }

输出:

 App: 1170ms 186ms 1171ms 1484ms 1227ms 204ms 1180ms 1177ms 1183ms 1155ms

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