在条件下加入2个连续的行 [英] join 2 consecutive rows under condition

问题描述

typeA;pointA1
typeA;pointA2
typeA;pointA3
typeB;pointB1
typeB;pointB2

结果输出将是:

typeA;pointA1;typeA;pointA2
typeA;pointA2;typeA;pointA3
typeB;pointB1;typeB;pointB2

是否可以为此目的使用sed或awk?

Is it possible to use sed or awk for this purpose?

推荐答案

使用awk可以轻松实现:

This is easy with awk:

awk -F';' '$1 == prevType { printf("%s;%s;%s\n", $1, prevPoint, $0) } { prevType = $1; prevPoint = $2 }'

我假设记录之间的空白行不属于输入；如果是这样，只需在awk之前通过grep -v '^$'运行输入即可.

I've assumed that the blank lines between the records are not part of the input; if they are, just run the input through grep -v '^$' before awk.

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