通过awk读取文件 [英] File read through awk
问题描述
我的文件包含下面的行，就像我想通过awk管理
I have file which contain line below like I want to manage through awk
文件名:-test.txt
filename:-test.txt
"A","@900",9999,"Test Place","Quayside Sc, Sligo, Tel: 071 9154382","SCRIPT",20150317
我要通过单个字符串"Quayside Sc，Sligo，Tel:071 9154382"来管理
I want to manage this is as single string "Quayside Sc,Sligo, Tel: 071 9154382"
当我执行以下命令时，它会自动在逗号前获取第一个字符串
It automatically take first string before comma when I perform following command
echo "A","@900",9999,"Test Place","Quayside Sc, Sligo, Tel: 071 9154382","SCRIPT",20150317 | awk -F ',' '{ print $4 "|" $8 }'
Test Place|SCRIPT
推荐答案
在gnu-awk中使用FPAT，您可以将整个引用的字符串作为单个字段获取:
Using FPAT in gnu-awk you can get whole quoted string as single field:
awk 'BEGIN{ FPAT="\"[^\"]*\"|[^,]*" } {print $4 ORS $5}' file
"Test Place"
"Quayside Sc, Sligo, Tel: 071 9154382"
FPAT="\"[^\"]*\"|[^,]*"使用正则表达式分解用引号引起来或用逗号分隔的字段.
FPAT="\"[^\"]*\"|[^,]*" uses a regex to break down fields surrounded by quotes or separated by comma.
出于演示目的，这里是每个已解析的字段:
For demo purpose here is each parsed field:
awk 'BEGIN{ FPAT="\"[^\"]*\"|[^,]*" } {for (i=1; i<=NF; i++) {
printf "$%d: <%s>\n", i, $i}}' file
$1: <"A">
$2: <"@900">
$3: <9999>
$4: <"Test Place">
$5: <"Quayside Sc, Sligo, Tel: 071 9154382">
$6: <"SCRIPT">
$7: <20150317>
更新:如果您没有gnu-awk 4，则可以使用此perl命令以达到相同的效果:
Update: If you don't have gnu-awk 4 then you can use this perl command for same effect:
perl -F',(?=(?:(?:[^\"]*\"){2})*[^\"]*$)' -ane 'print $F[3] . "\n" . $F[4] . "\n"' file
"Test Place"
"Quayside Sc, Sligo, Tel: 071 9154382"
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