如何从Java代码调用AWS Lambda函数/处理程序 [英] How to invoke the AWS lambda function / handler from Java code

问题描述

我是AWS lambda的新手，我已经创建了带有处理程序的lambda函数

I am new to AWS lambda I have created a lambda function with handler

example.Orders::orderHandler

这是自定义处理程序，现在我想从我的Java程序中调用此程序.

And this is the custom handler, now I want to invoke this from my Java program how do I need to this.

推荐答案

该类中的2种方法应该可以为您提供帮助.一种是用于需要传递有效载荷的情况，另一种是用于有效载荷为空的情况.

The 2 methods in this class should be able to help you. One is for if you need to pass in a payload, the other if the payload is null.

但是，您需要记住一件事:函数名称可能与处理程序不同(后者在此为example.Orders::orderHandler).调用处理程序功能时，将使用不处理程序名称.

However, you need to bear one thing in mind: the function name may not be the same as the handler (the latter here is example.Orders::orderHandler). The handler name is not used when invoking its function.

因此，如果您有一个具有函数名称'myFunction'的函数，并且在幕后调用您的example.Orders::orderHandler handler ，那么您将通过此函数下面的运行方法.

So, if you have a function with the function name 'myFunction' that behind the scenes call your example.Orders::orderHandler handler, then this is what you would pass into the run methods below.

import com.amazonaws.regions.Regions;
import com.amazonaws.services.lambda.AWSLambdaAsyncClient;
import com.amazonaws.services.lambda.model.InvokeRequest;
import com.amazonaws.services.lambda.model.InvokeResult;

class LambdaInvoker {

    public void runWithoutPayload(String region, String functionName) {
        runWithPayload(region, functionName, null);
    }

    public void runWithPayload(String region, String functionName, String payload) {
        AWSLambdaAsyncClient client = new AWSLambdaAsyncClient();
        client.withRegion(Regions.fromName(region));

        InvokeRequest request = new InvokeRequest();
        request.withFunctionName(functionName).withPayload(payload);
        InvokeResult invoke = client.invoke(request);
        System.out.println("Result invoking " + functionName + ": " + invoke);
    }
}

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