无法破坏Firebase连接，导致热Lambda失败，原因是"Firebase应用程序名称'[DEFAULT]'已经存在" [英] Cannot destroy Firebase connections making hot Lambda fail due to 'Firebase App name '[DEFAULT]' already exists'

问题描述

尝试各种可能要花费数小时的方法.

Been trying every approach I can think of for hours.

基本上，我正在运行一个AWS Lambda函数，该函数以客户端和服务器角色的身份对我的Firebase应用程序进行了一些工作.

Basically I'm running an AWS Lambda function which does some work to my Firebase app in both a client and server role.

在Lambda上，我需要能够反转firebase.initializeApp(config)和firebase.initializeApp(config, 'server').我已经尝试过firebase.app('server').delete()，但这似乎不起作用.

Being on Lambda, I need to be able to reverse the firebase.initializeApp(config) and firebase.initializeApp(config, 'server'). I've tried firebase.app('server').delete() but that doesn't seem to work.

在此先感谢您的帮助.

为澄清起见，我不能仅使用现有连接，因为配置可能会更改.

To clarify, I can't just use the existing connection because the config may change.

推荐答案

对initializeApp的调用采用可选的应用程序名称.如果未指定应用程序名称，则使用名称[DEFAULT].

Calls to initializeApp take an optional app name. If the app name is not specified, the name [DEFAULT] is used.

要取消初始化应用程序，您需要在应用程序实例上调用delete.该应用程序实例是通过initializeApp调用返回的，或者可以使用app函数获得.

To uninitialize an app, you need to call delete on the app instance. The app instance is returned by the initializeApp call or can be obtained using the app function.

也就是说，您可以像这样初始化和取消初始化应用程序:

That is, you can initialize and uninitialize an app like this:

app = firebase.initializeApp(configuration);
app.delete();

或者像这样:

firebase.initializeApp(configuration);
firebase.app('[DEFAULT]').delete();

请注意，delete函数返回的诺言将在应用程序删除完成时解决.

Note that the delete function returns a promise that resolves when the app deletion is complete.

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