在bash中遍历元组? [英] Loop over tuples in bash?

问题描述

是否可以在bash中遍历元组?

Is it possible to loop over tuples in bash?

作为一个例子，如果以下方法有效，那就太好了

As an example, it would be great if the following worked:

for (i,j) in ((c,3), (e,5)); do echo "$i and $j"; done

有没有一种解决方法，可以让我以某种方式遍历元组?

Is there a workaround that somehow lets me loop over tuples?

推荐答案

$ for i in c,3 e,5; do IFS=","; set -- $i; echo $1 and $2; done
c and 3
e and 5

关于set的这种用法(来自man builtins):

About this use of set (from man builtins):

在选项处理之后剩余的任何参数都被视为值 位置参数，并依次分配给$ 1，$ 2， ... $ n

Any arguments remaining after option processing are treated as values for the positional parameters and are assigned, in order, to $1, $2, ... $n

IFS=","设置字段分隔符，以便将每个$i正确地分割为$1和$2.

The IFS="," sets the field separator so every $i gets segmented into $1 and $2 correctly.

通过此博客.

更正确的版本，如@SLACEDIAMOND建议:

more correct version, as suggested by @SLACEDIAMOND:

$ OLDIFS=$IFS; IFS=','; for i in c,3 e,5; do set -- $i; echo $1 and $2; done; IFS=$OLDIFS
c and 3
e and 5

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