需要将文本文件的内容分配给bash脚本中的变量 [英] Need to assign the contents of a text file to a variable in a bash script

问题描述

我对制作bash脚本非常陌生，但是我的目标是获取我拥有的.txt文件，并将txt文件中的单词字符串分配给变量.我已经尝试过了(无论是否在正确的轨道上都不知道).

I am very new to making bash scripts, but my goal here is to take a .txt file I have and assign the string of words in the txt file to a variable. I have tried this (no clue if I am on the right track or not).

#!/bin/bash
FILE="answer.txt"
file1="cat answer.txt"
print $file1

运行此命令时，我会得到

When I run this, I get

Warning: unknown mime-type for "cat" -- using "application/octet-stream"
Error: no such file "cat"
Error: no "print" mailcap rules found for type "text/plain"

我该怎么做才能使这项工作成功?

What can I do to make this work?

编辑** 当我将其更改为:

Edit** When I change it to:

#!/bin/bash
    FILE="answer.txt"
    file1=$(cat answer.txt)
    print $file1

我反而得到了:

Warning: unknown mime-type for "This" -- using "application/octet-stream"
Warning: unknown mime-type for "text" -- using "application/octet-stream"
Warning: unknown mime-type for "string" -- using "application/octet-stream"
Warning: unknown mime-type for "should" -- using "application/octet-stream"
Warning: unknown mime-type for "be" -- using "application/octet-stream"
Warning: unknown mime-type for "a" -- using "application/octet-stream"
Warning: unknown mime-type for "varible." -- using "application/octet-stream"
Error: no such file "This"
Error: no such file "text"
Error: no such file "string"
Error: no such file "should"
Error: no such file "be"
Error: no such file "a"
Error: no such file "varible."

当我输入cat answer.txt时，它会打印出该文本字符串，该字符串应该像应该的那样是变量，但是，我仍然无法通过bash对该变量进行操作.

When I enter cat answer.txt it prints out this text string should be a varible like it should but, I still can't get the bash to do that with the varible.

推荐答案

您需要反引号以捕获命令的输出(并且您可能希望使用echo而不是print):

You need the backticks to capture output from a command (and you probably want echo instead of print):

file1=`cat answer.txt`
echo $file1

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