连接所有参数，并用双引号将它们引起来 [英] Concatenate all arguments and wrap them with double quotes

问题描述

function foo() {
A=$@...
echo $A
}

foo bla "hello ppl"

我希望输出为:
"bla""hello ppl"

I would like the output to be:
"bla" "hello ppl"

我需要做什么而不是省略号?

What do I need to do instead of the ellipsis?

推荐答案

@msw有正确的想法(在有关问题的评论中).但是，打印带引号的参数的另一个想法是:使用printf:

@msw has the right idea (up in the comments on the question). However, another idea to print arguments with quotes: use the implicit iteration of printf:

foo() { printf '"%s" ' "$@"; echo ""; }

foo bla "hello ppl"
# => "bla" "hello ppl"

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