删除字符，直到字符串中的某个字符为止 [英] Delete characters until a certain character from string

问题描述

如何使用bash删除字符串中的字符直到某个字符?

How can I delete characters from a string until a certain character with bash?

示例:

ananas1kiwi2apple1banana2tree

应如下所示:

apple1banana2tree

推荐答案

如果要使用bash参数扩展删除直到2的子字符串:

If you want to remove the substring upto 2, using bash parameter expansion:

${var#*2}

• #从左开始进行非贪婪匹配，将##用于贪婪

  • # does non-greedy match from left, use ## for greediness

    #*2匹配并丢弃变量var

    示例:

    $ var='ananas1kiwi2apple1banana2tree'
    $ echo "${var#*2}"
    apple1banana2tree
    

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