为什么在bash字符串相等性测试中出现意外的运算符错误? [英] Why am i getting an unexpected operator error in bash string equality test?

问题描述

第四行的错误在哪里?

if [ $bn == README ]; then

如果我将其写为

if [ $bn == README ]
then

或

if [ "$bn" == "README" ]; then

上下文:

for fi in  /etc/uwsgi/apps-available/* 
do 
        bn=`basename $fi .ini`
        if [ $bn == "README" ]
        then
                echo "~ ***#*** ~"
        else
                echo "## Shortend for convience ##"
        fi
done

推荐答案

您不能将==用于单括号比较([]).请改用single =.另外，您必须引用变量以防止扩展.

You can't use == for single bracket comparisons ([ ]). Use single = instead. Also you must quote the variables to prevent expansion.

if [ "$bn" = README ]; then

如果使用[[]]，则可能适用，并且不需要引用第一个参数:

If you use [[ ]], that could apply and you wouldn't need to quote the first argument:

if [[ $bn == README ]]; then

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