如何使用BASH从文件名中删除特定字符 [英] How do I Remove Specific Characters From File Names Using BASH

问题描述

我要删除的文件中有很多文件具有共享模式.例如，我有文件"a_file000.tga"和"another_file000.tga".我想对那些文件进行操作，以从其名称中删除模式"000"，从而得到新名称"a_file.tga"和"another_file.tga".

I have a lot of files that have a shared pattern in their name that I would like to remove. For example I have the files, "a_file000.tga" and "another_file000.tga". I would like to do an operation on those files that would remove the pattern "000" from their names resulting in the new names, "a_file.tga" and "another_file.tga".

推荐答案

尝试一下(这也适用于普通的Bourne sh):

Try this (this works in plain old Bourne sh as well):

for i in *000.tga
do
    mv "$i" "`echo $i | sed 's/000//'`"
done

两个参数都用引号引起来，以支持文件名中的空格.

Both arguments are wrapped in quotes to support spaces in the filenames.

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