如何检查今天是否是周末狂欢? [英] How to check if today is a weekend in bash?

问题描述

如何查看今天是周末还是bash甚至perl?

How to check if today is a weekend using bash or even perl?

我想阻止某些程序在周末运行.

I want to prevent certain programs to run on a weekend.

推荐答案

您可以使用类似以下内容的

You can use something like:

if [[ $(date +%u) -gt 5 ]]; then echo weekend; fi

date +%u为您提供从星期一(1)到星期日(7)的星期几.如果大于5(周六为6，周日为7)，则为周末.

date +%u gives you the day of the week from Monday (1) through to Sunday (7). If it's greater than 5 (Saturday is 6 and Sunday is 7), then it's the weekend.

因此您可以在脚本顶部放置以下内容:

So you could put something like this at the top of your script:

if [[ $(date +%u) -gt 5 ]]; then
    echo 'Sorry, you cannot run this program on the weekend.'
    exit
fi

或更简洁:

[[ $(date +%u) -gt 5 ]] && { echo "Weekend, not running"; exit; }

要检查是否为工作日，请使用相反的含义(< 6而不是> 5):

To check if it's a weekday, use the opposite sense (< 6 rather than > 5):

$(date +%u) -lt 6

这篇关于如何检查今天是否是周末狂欢?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！