执行包含shell变量引号的命令 [英] Execute command containing quotes from shell variable

问题描述

我目前在从shell变量执行命令时遇到问题.

I'm currently having problems to execute a command from a shell variable.

通常，以下功能可以正常工作:

In general the following works as expected:

COMMAND="echo A"
echo $COMMAND
$COMMAND

产生:

echo A
A

但如果我这样做

COMMAND="su aUser -s /bin/bash -c 'echo A'"
echo $COMMAND
$COMMAND

我知道

su aUser -s /bin/bash -c 'echo A'
Password: 
A': -c: line 0: unexpected EOF while looking for matching `''
A': -c: line 1: syntax error: unexpected end of file

如果我输入这一行

su aUser -s /bin/bash -c 'echo A'

直接按预期工作.

似乎我认为$ COMMAND等于直接以命令形式输入内容是错误的.

It seems my assumption that $COMMAND is equal to entering the content as command directly is wrong.

1)有人知道我如何从变量中运行命令吗?

1) Does anyone know how I can run the command from a variable?

2)两者之间到底有什么区别

2) What exactly is the difference between

COMMAND="command"
$COMMAND

和

command

?

推荐答案

数组对于保持参数完整很有用:

Arrays are useful to keep your parameters whole:

command=(su aUser -s /bin/bash -c 'echo A')

并完全像这样调用它:

"${command[@]}"

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