Unix命令行历史记录替换^ foo ^ bar(用于多次替换) [英] Unix commandline history substitution ^foo^bar (for multiple replacements)

问题描述

有时我会使用bash命令替换上一个命令中的字符串:

Occasionally I use the bash command to replace string in previous command:

^foo^bar

今天，我想在下一行进行替换，以将所有出现的checkbox替换为`radio:

Today I wanted to make the replacement in the following line for replacing all occurrences of checkbox with `radio:

$ git mv _product_checkbox_buttons.html.erb _product_checkbox_button.html.erb
$ ^checkbox^radio
git mv _product_radio_buttons.html.erb _product_checkbox_button.html.erb

因此，它仅替换第一次出现的情况.如何使它替换所有出现的内容?

So it only replaces the first occurrence. How do I make it replace all occurrences?

bash --version
GNU bash, version 3.2.48(1)-release (x86_64-apple-darwin10.0)
Copyright (C) 2007 Free Software Foundation, Inc.

推荐答案

man bash说^old^new等同于!!:s/old/new/.您要!!:gs/old/new/全局替换.

man bash says ^old^new is equivalent to !!:s/old/new/. You want !!:gs/old/new/ to globally replace.

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