AngularJS检查的形式是有效控制 [英] AngularJS check if form is valid in controller
本文介绍了AngularJS检查的形式是有效控制的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我需要检查,如果一种形式是在控制有效。
查看:
<形式的novalidate =
NAME =createBusinessForm
NG-提交=setBusinessInformation()
类=CSS-形式>
<! - 场 - >
< /表及GT;
在我的控制器:
.controller(
BusinessCtrl',
功能($范围,$ HTTP,$位置,商务,的BusinessService,
UserService,照片)
{ 如果($ scope.createBusinessForm $有效){
$ scope.informationStatus =真;
} ...
我得到这个错误:
类型错误:无法读取属性未定义'$有效
解决方案
我已经更新控制器:
.controller('BusinessCtrl',
功能($范围,$ HTTP,$位置,商务,的BusinessService,UserService,照片){
$范围。$腕表('createBusinessForm。$有效',函数(的newval){
//$scope.valid =的newval;
$ scope.informationStatus =真;
});
...
I need to check if a form is valid in a controller.
View:
<form novalidate=""
name="createBusinessForm"
ng-submit="setBusinessInformation()"
class="css-form">
<!-- fields -->
</form>
In my controller:
.controller(
'BusinessCtrl',
function ($scope, $http, $location, Business, BusinessService,
UserService, Photo)
{
if ($scope.createBusinessForm.$valid) {
$scope.informationStatus = true;
}
...
I'm getting this error:
TypeError: Cannot read property '$valid' of undefined
解决方案
I have updated the controller to:
.controller('BusinessCtrl',
function ($scope, $http, $location, Business, BusinessService, UserService, Photo) {
$scope.$watch('createBusinessForm.$valid', function(newVal) {
//$scope.valid = newVal;
$scope.informationStatus = true;
});
...
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