在bash脚本中使用find命令 [英] Using find command in bash script

问题描述

我刚刚开始使用bash脚本，我需要使用具有多种文件类型的find命令.

I just start to use bash script and i need to use find command with more than one file type.

list=$(find /home/user/Desktop -name '*.pdf') 

此代码适用于pdf类型，但我想一起搜索多个文件类型，例如.txt或.bmp.您有任何想法吗?

this code work for pdf type but i want to search more than one file type like .txt or .bmp together.Have you any idea ?

推荐答案

欢迎使用bash.这是一件古老，黑暗而神秘的东西，具有强大的魔力. :-)

Welcome to bash. It's an old, dark and mysterious thing, capable of great magic. :-)

您要询问的选项是find命令，而不是bash.在命令行中，您可以man find查看选项.

The option you're asking about is for the find command though, not for bash. From your command line, you can man find to see the options.

您要查找的是-o表示或":

The one you're looking for is -o for "or":

  list="$(find /home/user/Desktop -name '*.bmp' -o -name '*.txt')"

那表示... 不要这样做. 这样的存储可能适用于简单的文件名，但是一旦您必须处理特殊字符(例如空格和换行符，所有赌注都关闭了.有关详细信息，请参见 ParsingLs .

$ touch 'one.txt' 'two three.txt' 'foo.bmp'
$ list="$(find . -name \*.txt -o -name \*.bmp -type f)"
$ for file in $list; do if [ ! -f "$file" ]; then echo "MISSING: $file"; fi; done
MISSING: ./two
MISSING: three.txt

路径名扩展(globbing)提供了一种更好/更安全的方式来跟踪文件.然后，您还可以使用bash数组:

Pathname expansion (globbing) provides a much better/safer way to keep track of files. Then you can also use bash arrays:

$ a=( *.txt *.bmp )
$ declare -p a
declare -a a=([0]="one.txt" [1]="two three.txt" [2]="foo.bmp")
$ for file in "${a[@]}"; do ls -l "$file"; done
-rw-r--r--  1 ghoti  staff  0 24 May 16:27 one.txt
-rw-r--r--  1 ghoti  staff  0 24 May 16:27 two three.txt
-rw-r--r--  1 ghoti  staff  0 24 May 16:27 foo.bmp

Bash FAQ 还有许多其他有关bash编程的优秀技巧.

The Bash FAQ has lots of other excellent tips about programming in bash.

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