HTTP通过基本身份验证获取Android [英] HTTP Get Android with Basic Auth

问题描述

我是REST服务的新手，我正在网上寻找几个小时...

I'm new to REST services and I'm looking for a few hours around the web...

我有一个REST服务网址，可以返回 JSON数据. 登录名(用户名和密码)为基本身份验证. 我正在寻找一个简单的库/代码段，该代码段可让我插入uri，用户名&密码，然后将JSON字符串还给我.

I have a REST service url that gives me back JSON data. The login (username & password) are basic auth. I'm looking for a simple library/code snippet that lets me insert the uri, username & password and give me back the JSON string.

任何帮助将不胜感激！

推荐答案

也许您可以尝试以下方法:

Maybe you can try something like this:

StringBuilder builder = new StringBuilder();
HttpClient client = new DefaultHttpClient();
HttpGet httpGet = new HttpGet("YOUR WEBSITE HERE");

// Add authorization header
httpGet.addHeader(BasicScheme.authenticate( new UsernamePasswordCredentials("user", "password"), "UTF-8", false));

// Set up the header types needed to properly transfer JSON
httpGet.setHeader("Content-Type", "application/json");
try {
      HttpResponse response = client.execute(httpGet);
      StatusLine statusLine = response.getStatusLine();
      int statusCode = statusLine.getStatusCode();
      if (statusCode == 200) {
        HttpEntity entity = response.getEntity();
        InputStream content = entity.getContent();
        BufferedReader reader = new BufferedReader(new InputStreamReader(content));
        String line;
        while ((line = reader.readLine()) != null) {
          builder.append(line);
        }
      } else {
        Log.e(ParseJSON.class.toString(), "Failed to download file");
      }
} catch (ClientProtocolException e) {
  e.printStackTrace();
} catch (IOException e) {
  e.printStackTrace();
}

关于编写JSONObject的信息，请查看以下代码片段:

As for writing a JSONObject, check out this code snippet:

public void writeJSON() {
  JSONObject object = new JSONObject();
  try {
    object.put("name", "Jack Hack");
    object.put("score", new Integer(200));
    object.put("current", new Double(152.32));
    object.put("nickname", "Hacker");
  } catch (JSONException e) {
    e.printStackTrace();
  }
  System.out.println(object);
} 

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